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Makovka662 [10]
3 years ago
6

If 200 grams of water is to be heated from 24.0oC to 100.0oC to make a cup of tea, how much heat must be added?

Chemistry
1 answer:
aksik [14]3 years ago
3 0
According to this formula:

Q = M*C*ΔT 

when we have M ( the mass of water) = 200 g 

and C ( specific heat capacity ) of water = 4.18 J/gC

ΔT (the difference in temperature) = Tf - Ti 
     
                                                          = 100 - 24

                                                          = 76°C

So by substitution:


Q = 200 g * 4.18 J/gC * 76 °C

   = 63536 J 

 ∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J


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Answer:

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Explanation:

Hello!

In this case, when two substances at different temperature are put in contact and an equilibrium temperature is attained, we can evidence that the heat lost by the hot substance (metal) is gained by the cold substance (water) and we can write:

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Best regards.

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