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How does trace evidence end up transferring to the crime scene, suspect, or victim? Discuss some of the ways that this might hap

disa [49]

Trace evidence can end up transferring to the crime scene through Locard's Exchange Principle, which states that whenever two things come into contact with one another, there is an exchange of physical material A.K.A evidence. This exchange is most often done through physical contact, such as a struggle or a suspect attempting to hide evidence or alter the crime scene. It can even involve a suspect's shirt sleeve brushing against some wet paint.

I hope I helped!

3 0

3 years ago

Why is chromatography particularly well suited to the needs of a drug analyst

Zarrin [17]

Chromatography is used in purification. Drugs analysts may use the technique to separate the active molecule in a drug molecule, for efficacy or toxicity analysis, from the other drug components.

Explanation:

Chromatography is used to separate a mixture of different components based on the size of their molecules. In liquid chromatography, the mixture is dissolved in a solvent that acts as the mobile phase and then passed along a stationary phase with different kinds of pores, As the mixture passes through the pores, their different components are separated because they take different times to pass through the stationary phase because of their different rates in passing through the pores.

In gas chromatography, a gas is used as a mobile phase while a liquid is used as the stationary phase.

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For more on chromatography check out;

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6 0

3 years ago

Why do we crack molecules?

tino4ka555 [31]

We need to crack molecules in order for us to get the desired molecule. For example, in the extraction of crude oil, after entering the fractional distillation, it will give products base on their molecular structure. The products are gasoline, diesel fuel, jet fuel, wax, asbestos,kerosene.

4 0

3 years ago

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450g of chromium(iii) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (ANS

Irina18 [472]

Answer:

600 g K₂SO₄

Explanation:

First write down the complete, balanced chemical equation for such question. In this case:

Cr₂(SO₄)₃ + 2K₃PO₄ → 3K₂SO₄ + 2CrPO₄

Next, calculate molar masses of required compounds mentioned in the question. In this case it is for Cr₂(SO₄)₃ and K₂SO₄.

Molar mass(MM) of Cr₂(SO₄)₃:

= 2*(MM of Cr) + 3*( MM of S) + 3*4*( MM of O)

= 2*(52) + 3*(32) + 12*(16)

= 104 + 96 + 192

= 392 g

Molar mass(MM) of K₂SO₄:

= 2*(MM of K) + 1*( MM of S) + 4*( MM of O)

= 2*(39) + 32 + 4*(16)

= 78 + 32 + 64

= 174 g

Here comes the concept of Limiting reagent:

The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it. The other reactants present with this are usually in excess and called excess reactants. If quantities of both the reactants are given, then one should apply unitary method and find out the limiting reagent out of the two. Then, determine the amount of product formed or percentage yield.

Also, 1 mole( 392 g) of Cr₂(SO₄)₃ gives 3 moles( 174*3 = 522 g) of K₂SO₄.

Using unitary method, if 392g of Cr₂(SO₄)₃ gives 522 g of K₂SO₄ , then 450 g of Cr₂(SO₄)₃ will give how much of K₂SO₄?

Yeild of K₂SO₄ : $\frac{522 * 450}{392}$

That is 599.3 g.

Since we have not considered molecular masses of individual atoms to 6 decimal places, this number can be approximated to 600g.

Therefore, 600g of K₂SO₄ is produced.

6 0

3 years ago

Individual measurements introduce errors that may be large or small depending on the quality of the tools and processes used. Sc

kirill [66]

Answer:

B. accepted value x 0.1

Explanation:

in the equation provided

$Percentage Error=\frac{Error}{AcceptedValue} X100$

Maximum allowed value of percentage error = 10%

put this value in the equation in stead of percentage error we get,

$10 = \frac{error}{AcceptedValue} X100\\ \frac{10}{100} =\frac{error}{AcceptedValue}\\.1=\frac{error}{AcceptedValue}\\error = .1 X Accepted Value$

so maximum error = .1 x accepted value

10 % percentage error means the experimental value has 10 % error compared to accepted value.so error will be 10 % of the accepted value

or .1 times of accepted value

8 0

3 years ago