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Ann [662]
3 years ago
15

What is the chemical equation for diphosphorus trioxide + water ---> phosphorous acid?

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
6 0
Your answer is P_{2}O_{3}+3H_{2}O\rightarrow\ 2H_{3}PO_{3}

but if you are looking for some explanation check description below :)

Diphosphorus trioxide formula is:

P_{2}O_{3}

Di stands from 2 atoms of something, in this case we have 2 atoms of Phosphorus.

Trioxide means that we have 3 atoms of oxygen in this substance that's why we have: P_{2}O_{3}

And water is just H_{2}O

Unbalanced formula is:

P_{2}O_{3}+H_{2}O\rightarrow\ H_{3}PO_{3}

Now we need to balance this equation

On left hand side we have 2 atoms of Phosphorus, on right hand side we have just one atom of Phosphorus, that's why we need to put 2 before H_{3}PO_{3}

Now we need to count all atoms of oxygen and hydrogen and make it equal on both side.

So we need to put 3 on left hand side before water to make this equation balanced.
That's why correct answer is:
P_{2}O_{3}+3H_{2}O\rightarrow\2H_{3}PO_{3}
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Complete and balance the following neutralization reaction Ca(OH)2 + H2SO4
Debora [2.8K]

Answer: Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + 2H2O(l)

Explanation:

Since this is a neutralization reaction, the end product would be salt and water. In this equation Calcium will displace hydrogen from the acid because it is more reactive, resulting in the formation of CaSO4 (salt), while the displaced H2 molecule combines with OH molecules to form water.

The equation of the reaction is thus;

Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + H2O(l), in other to balance it, we add ''2'' to the water molecule in the right hand side of the equation.

Balance equation is  

Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + 2H2O(l)

6 0
3 years ago
CH4(g) gas reacts with F2(g) to produce CH3F(g) and HF(g) .
Ugo [173]

Answer:

I am looking for this as well. Can someone please help!

Explanation:

6 0
3 years ago
Read 2 more answers
How many molecules units are in 4.5 moles of CF4
kobusy [5.1K]
1.0 mole ---------- 6.02x10²³ molecules
4.5 moles -------- ?

4.5 * 6,02x10²³ / 1.0

= 2.709x10²⁴ molecules units
7 0
3 years ago
Picture of gas laws question below:
Vera_Pavlovna [14]

Volume of the tank is 5.5 litres.

Explanation:

mass of the CO2 is given 8.6 grams

Pressure of the gas is 89 Kilopascal which is 0.8762 atm

Temperature of the gas is 29 degrees ( 0 degrees +273.5= K) so (29+273)

R = gas constant 0.0821 liter atmosphere per kelvin)

FROM THE IDEAL GAS LAW

PV=nRT ( P Pressure, V Volume, n is number of moles of gas, R gas constant, Temperature in Kelvin)

no of moles = mass/atomic mass

                    =  8.6/44

                    = 0.195 moles

now putting the values in equation

V=nRT/P

  = 0.195*0.0821*302/ 0.8762

  = 5.5 litres.

As the carbon dioxide gas occupies the volume os the tank hence volume of tank is 5.5 litres.

4 0
3 years ago
A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

q water = mcΔT

Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

qwater = 247.19 J

qcopper = 215 x 0.385 x (Ti-24.4)

              = 82.77Ti - 2019.71

Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

Ti = 27.38 degrees

8 0
3 years ago
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