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Ann [662]
3 years ago
15

What is the chemical equation for diphosphorus trioxide + water ---> phosphorous acid?

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
6 0
Your answer is P_{2}O_{3}+3H_{2}O\rightarrow\ 2H_{3}PO_{3}

but if you are looking for some explanation check description below :)

Diphosphorus trioxide formula is:

P_{2}O_{3}

Di stands from 2 atoms of something, in this case we have 2 atoms of Phosphorus.

Trioxide means that we have 3 atoms of oxygen in this substance that's why we have: P_{2}O_{3}

And water is just H_{2}O

Unbalanced formula is:

P_{2}O_{3}+H_{2}O\rightarrow\ H_{3}PO_{3}

Now we need to balance this equation

On left hand side we have 2 atoms of Phosphorus, on right hand side we have just one atom of Phosphorus, that's why we need to put 2 before H_{3}PO_{3}

Now we need to count all atoms of oxygen and hydrogen and make it equal on both side.

So we need to put 3 on left hand side before water to make this equation balanced.
That's why correct answer is:
P_{2}O_{3}+3H_{2}O\rightarrow\2H_{3}PO_{3}
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1) Chemical reaction 1: 4Cu + O₂ →  2Cu₂O.
n(Cu) = 88,8 ÷ 63,55.
n(Cu) = 1,4.
n(O) = 11,2 ÷ 16.
n(O) = 0,7.
n(Cu) : n(O) = 1,4 : 0,7.
n(Cu) : n(O) = 2 : 1.
Compound is Cu₂O.
2) Chemical reaction 2: 2Cu + O₂ →  2CuO.
n(Cu) = 79,9 ÷ 63,55.
n(Cu) = 1,257.
n(O) = 20,1 ÷ 16.
n(O) = 1,257.
n(Cu) : n(O) = 1,257 : 1,257.
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6 0
3 years ago
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slega [8]

Answer:

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Explanation:

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Which of the following expressions is the correct equilibrium-constant expression for the equilibrium between dinitrogen tetroxi
nekit [7.7K]

Answer:

D. [NO₂]²/[N₂O₄]

Explanation:

The equilibrium constant expression for a reaction is products over reactants. Since NO₂ has a coefficient of 2, it will become an exponent.

So, it would be:

[NO₂]²/[N₂O₄]

Hope that helps.

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Answer:

AgNO3 -soluble in water

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AgI- Insoluble in water

Explanation:

The solubility of chemical compounds in water is easily predicted by a set of rules generally referred to as the solubility rules. These rules are usually based on experimental observation of diverse groups of compounds.

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Answer:

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