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Ann [662]
3 years ago
15

What is the chemical equation for diphosphorus trioxide + water ---> phosphorous acid?

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
6 0
Your answer is P_{2}O_{3}+3H_{2}O\rightarrow\ 2H_{3}PO_{3}

but if you are looking for some explanation check description below :)

Diphosphorus trioxide formula is:

P_{2}O_{3}

Di stands from 2 atoms of something, in this case we have 2 atoms of Phosphorus.

Trioxide means that we have 3 atoms of oxygen in this substance that's why we have: P_{2}O_{3}

And water is just H_{2}O

Unbalanced formula is:

P_{2}O_{3}+H_{2}O\rightarrow\ H_{3}PO_{3}

Now we need to balance this equation

On left hand side we have 2 atoms of Phosphorus, on right hand side we have just one atom of Phosphorus, that's why we need to put 2 before H_{3}PO_{3}

Now we need to count all atoms of oxygen and hydrogen and make it equal on both side.

So we need to put 3 on left hand side before water to make this equation balanced.
That's why correct answer is:
P_{2}O_{3}+3H_{2}O\rightarrow\2H_{3}PO_{3}
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When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t
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First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

where,

m = mass of solution = 100 g

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T_{final} = final temperature = 23.1^oC

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Now put all the given values in the above formula, we get:

q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

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Now we have to calculate the enthalpy change during the reaction.

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\Delta H = enthalpy change = ?

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