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Ann [662]
3 years ago
15

What is the chemical equation for diphosphorus trioxide + water ---> phosphorous acid?

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
6 0
Your answer is P_{2}O_{3}+3H_{2}O\rightarrow\ 2H_{3}PO_{3}

but if you are looking for some explanation check description below :)

Diphosphorus trioxide formula is:

P_{2}O_{3}

Di stands from 2 atoms of something, in this case we have 2 atoms of Phosphorus.

Trioxide means that we have 3 atoms of oxygen in this substance that's why we have: P_{2}O_{3}

And water is just H_{2}O

Unbalanced formula is:

P_{2}O_{3}+H_{2}O\rightarrow\ H_{3}PO_{3}

Now we need to balance this equation

On left hand side we have 2 atoms of Phosphorus, on right hand side we have just one atom of Phosphorus, that's why we need to put 2 before H_{3}PO_{3}

Now we need to count all atoms of oxygen and hydrogen and make it equal on both side.

So we need to put 3 on left hand side before water to make this equation balanced.
That's why correct answer is:
P_{2}O_{3}+3H_{2}O\rightarrow\2H_{3}PO_{3}
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1) Calculate the mass of water:

mass of water = mass of the hydrate CuSO4 - mass of the anhydrous compound

mass of water = 12.98 g - 9.70 g = 3.28g

2) Calculate the number of moles of water

number of moles = mass in grams / molar mass

molar mass of water = 18.01 g/mol

number of moles of water = 3.28 g / 18.01 g/mol = 0.182 mol

3) Calculate the number of moles of CuSO4 anhydrous

number of moles = mass in grams / molar mass

molar mass of Cu SO4 = 159.6 g/mol

number of moles of CuSO4 = 9.70g / 159.6 g/mol = 0.0608 moles

4) Calculate the ratio moles of water / moles of CuSO4

ratio = moles of water / moles of CuSO4 = 0.182 / 0.0608 = 2.99 ≈ 3

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