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3 years ago

Unit rate of 100 calories in 5 crackers

Mathematics

2 answers:

amid [387]3 years ago

7 0

Answer:

20.

Step-by-step explanation:

Nimfa-mama [501]3 years ago

5 0

Answer:

Step-by-step explanation:

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Find the solution by graphing the equations pls help

lilavasa [31]

Answer:

graph these
y = 2x + 2
y = 2x - 3

Step-by-step explanation:

2x - y = -2
2x - y = 3

convert to y intercept form
first
2x - y = -2
-y = -2x - 2
y = 2x + 2
second
2x - y = 3
-y = -2x + 3
y = 2x - 3

you are left with
y = 2x + 2
y = 2x - 3
i cannot graph these for you, but i assume you know how, there is no solution because the lines are parallel

4 0

3 years ago

ECA is a semi equilateral triangle at C,

stiks02 [169]

Answer: its 50

Step-by-step explanation:

6 0

2 years ago

The circumference of a circle can be found using the formula C = 2 nr.

victus00 [196]

Radius = circumference/2(3.14)
OPTION 3

5 0

3 years ago

Read 2 more answers

Given that 'n' is any natural numbers greater than or equal 2. Prove the following Inequality with Mathematical Induction

Oliga [24]

The base case is the claim that

$\dfrac11 + \dfrac12 > \dfrac{2\cdot2}{2+1}$

which reduces to

$\dfrac32 > \dfrac43 \implies \dfrac46 > \dfrac86$

which is true.

Assume that the inequality holds for n = k ; that

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k > \dfrac{2k}{k+1}$

We want to show if this is true, then the equality also holds for n = k + 1 ; that

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2(k+1)}{k+2}$

By the induction hypothesis,

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2k}{k+1} + \dfrac1{k+1} = \dfrac{2k+1}{k+1}$

Now compare this to the upper bound we seek:

$\dfrac{2k+1}{k+1} > \dfrac{2k+2}{k+2}$

because

$(2k+1)(k+2) > (2k+2)(k+1)$

in turn because

$2k^2 + 5k + 2 > 2k^2 + 4k + 2 \iff k > 0$

6 0

2 years ago

Read 2 more answers

Choose the correct answer choice please show steps!!

sladkih [1.3K]

Answer:

$\large\boxed{B.\ \cos(37^o)=\dfrac{x}{14}}$

Step-by-step explanation:

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\\text{We have}\ adjacent=x\ \text{and}\ hypotenuse=14.\\\text{Therefore it's a cosine.}$

6 0

3 years ago

Unit rate of 100 calories in 5 crackers​

Unit rate of 100 calories in 5 crackers