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Alex777 [14]
3 years ago
10

Please help 5 questions I need help

Mathematics
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

1. <2, <7

2. 58

3. 78

4. a and b

h5. <2 and <7 ( i think this is the same question as the first one)

Step-by-step explanation:

2. 2x + 7 = 123 (you have to make them equal to each other because they are consecutive interior angles)

2x + 7 = 123, subtract 7

2x = 116, divide 2 for both sides to make x by itself

x = 58

3. 78 because of consecutive interior angles

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Enter the explicit rule for the sequence
pogonyaev

ANSWER

a_n= \frac{2}{5} ( {5}^{n - 1} )

EXPLANATION

The recursive rule for the geometric sequence is

a_1=\frac{2}{5} ;a_n=5a_{n-1}

This implies that:

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r = 5

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a_n= \frac{2}{5} ( {5}^{n - 1} )

6 0
3 years ago
Which sum is equal to the expression - 5x3 + 2x2 + 9x+2/<br> (x²+ 2)²
Makovka662 [10]

Answer:

Option C

Step-by-step explanation:

Given expression is \frac{-5x^3+2x^2+9x+2}{(x^2+2)^2}

Option A

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= \frac{A(x^2+2)}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{Ax^2+2A+Bx+C}{(x^2+2)^2}

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Therefore, both the expressions are not equivalent.

Option B

\frac{A}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{A+Bx+C}{(x^2+2)^2}

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Option C

\frac{Ax+B}{(x^2+2)}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{(Ax+B)(x^2+2)}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{Ax^3+Bx^2+2Ax+2B+Cx+D}{(x^2+2)^2}

= \frac{Ax^3+Bx^2+x(2A+C)+D}{(x^2+2)^2}

Here, numerator is a cubic polynomial.

Therefore, both the expressions are equivalent.

Option D

\frac{Ax+B}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}

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Numerator is a linear polynomial.

Therefore, sum is not equal to the given expression.

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3 0
3 years ago
which of the following correctly describes the end behavior of the polynomial function f(x)=-x^3+x^2-4x+2
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Answer:

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Lets solve the function first and then find out the end behavior of the polynomial:

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Therefore the end behavior of the given function will be described as "the the left end goes up and the right end goes down"....

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3 years ago
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