Answer:
Step-by-step explanation:
(jk^-2/j^-1k^-3)^3
(-2)(-1)^-2
------------- ^3
(-2)^-1(-1)^-3
switch negative exponenst to other side
(-2)(-2)(-1)^3
__________
(-1)^2
4(-1)
-----
1
= -4
REMEMBER all to the 3rd power!
(-4)^3
-64
By defining how exponents work, we conclude that 4^3 = 64, so the correct option is A.
<h3>
How to find the cube of 4?</h3>
Let's remember how exponents work.
If we have a number a to the exponent n:
a^n
It means that we need to multiply the number a by itself n times.
Then, in this case:
4^3
Can be rewritten to.
4*4*4
Now we can solve that product:
4*4*4 = (4*4)*4 = 16*4 = 64
Then we conclude that the correct option is A
4^3 = 64
If you want to learn more about exponents:
brainly.com/question/847241
#SPJ1
Answer:
Step-by-step explanation:
We have been given the equation
and we are asked to apply the square root property of equality to our given a equation and isolate the variable
First, take the square root of both sides of our equation
<em>THEREFORE, THERE ARE TWO SOLUTIONS FOR OUR GIVEN EQUATION</em>
<em>
</em>
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8/18 because just times them by 2 and it will be 8/28.
I assume that you want the measurement of angle A
A + (A + 38) = 90
angle A + (38 more than angle a) = are complementary
2A = 52
A = 26
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