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2 years ago

If f(x) =3/2x +14 then find the value of f(0)

Mathematics

2 answers:

IgorC [24]2 years ago

7 0

$\huge{\mathbb{\tt {PROBLEM:}}}$

${\boxed{\boxed{\tt {If f(x) =3/2x +14 \: then \: find \: the \: value \: of \: f(0)}}}}$

$\huge{\mathbb{\tt {ANSWER:}}}$

${\mathbb{14}}$

$\huge{\mathbb{\tt {EXPLANATION:}}}$

${\boxed{\boxed{\tt {You \: must \: be \: replaced \: each \: instance \: of \: x \: with \: 0 \: to \: find \: f(0)}}}}$

${\boxed{\boxed{\tt { f(0)=(3/2)(0)+14=14}}}}$

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Neko [114]2 years ago

3 0

Answer:

Step-by-step explanation:

Replace each instance of x with 0 to find f(0):

f(0) = (3/2)(0) + 14 = 14

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Factor x2+4x+3.

Alexxx [7]

Answer:

c. (x +3)(x + 1)

Step-by-step explanation:

Factoring an equation is a way of expressing an equation as the product of other linear expressions. The following expression,

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Can be represented as the product of the following,

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$(x+3)(x+1)\\$

Distribute,

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Simplify,

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3 years ago

Determine if (-2,6) and (4,12) are solutions to the system of equations:

kykrilka [37]

Answer:

Both $(-2,6)$ and $(4,12)$ are solutions to the system.

Step-by-step explanation:

In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.

Step 1: Plug $(-2,6)$ into $y=x+8$

$(6) = (-2)+8 = 6$

The solution verifies the equation.

Step 2: Plug $(-2,6)$ into $2y=x^2 + 8$

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The solution verifies both equations. Therefore, $(-2,6)$ is a solution to this system.

Now we must check if the second point is also valid.

Step 3: Plug $(4,12)$ into $y=x+8$

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Step 4: Plug $(4,12)$ into $2y=x^2 + 8$

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The solution verifies both equations. Therefore, $(4,12)$ is another solution to this system.

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