Answer:
B) FALSE.
Explanation:
First off, its important to understand the following concepts;
A half reaction is either the oxidation or reduction reaction component of a redox (Oxidation - Reduction) reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.
Often, the concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).
Half equations simply much just breaks the reaction into oxidation and reduction steps (irrespective of the order, whether left or right).
An example of half equation is given below;
Mg → Mg2+ + 2e− (Oxidation)
Cu2+ + 2e− → Cu (Reduction)
The answer is false because; oxidation-reduction reactions are NOT represented by equations that group the reaction participants into reactants and products. Rather they are
The formal charge on each atom can be known by counting up the number of valence electrons that is present on each atom.
<h3>What is Lewis structure?</h3>
The term Lewis structure is the representation of a compound using its symbols and showing the valence electrons as dots. This question is incomplete as the Lewis structures were not shown.
If it is shown, we can know the formal charge on each atom by counting up the number of valence electrons that is present on each atom.
Learn more about Lewis structure: brainly.com/question/4144781
The relationship between independent and dependent variables is constant. The independent variables are not affected and do not change while dependent variables rely on something or a particular change.
Hope this helps and have a good day/night!
Answer:
Mass = 112 g
Explanation:
Given data:
Mass of CO₂ produced = 90.6 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂+ 4H₂O
Number of moles of CO₂:
Number of moles = 90.6 g/ 44 g/mol
Number of moles = 2.1 mol
Now we will compare the moles of CO₂ and oxygen:
CO₂ : O₂
3 : 5
2.1 : 5/3×2.1 = 3.5
Mass of oxygen needed:
Mass = number of moles × molar mass
Mass = 3.5 mol × 32 g/mol
Mass = 112 g
Molecules arranged in regular pattern changes into an irregular pattern
