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2 years ago

Which of the following is not one of the three common forms of matter

Chemistry

1 answer:

Gnesinka [82]2 years ago

3 0

Answer:

Plasma.

Explanation:

The three common forms of matter are liquids, solids, and gases.

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1. Calculate the average atomic mass of rubidium. Rubidium has two isotopes, 85Rb and 87Rb. 85Rb has an atomic mass of 84.912 am

DiKsa [7]

Just use labels I’m lazy

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2 years ago

Indicate which reaction will occur faster. explain your reasoning. select the single best answer. solvolysis of 1−chloro−2,2−dim

Radda [10]

The tert-butyl chloride in ethanol would surely react faster than the solvolysis of 1-chloro-2,2-dimethyl propane. It is known that both reactions are under the SN2 category so it would be hard for these reactions to occur. However, SN1 reactions are possible because of the ethanol which is a polar solvent. Both would form carbocations but tert-butyl chloride forms a more stable carbocation while the 1-chloro-2,2-dimethyl propane forms a primary carbocation only.

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3 years ago

Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres

yulyashka [42]

Answer: The freezing point of solution is -0.454°C

Explanation:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

$K_f$ = molal freezing point elevation constant = 1.86°C/m

$m_{solute}$ = Given mass of solute (KCl) = 5.0 g

$M_{solute}$ = Molar mass of solute (KCl) = 74.55 g/mol

$W_{solvent}$ = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

$0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC$

Hence, the freezing point of solution is -0.454°C

3 0

2 years ago

A compound contains nitrogen and a metal. This compound goes through a combustion reaction such that compound X is produced from

tia_tia [17]

Answer:

The correct answer is: X is nitrogen dioxide, and Y is a metal oxide

Explanation:

Combustion of compound of containing nitrogen and metal will give nitrogen dioxide and metal oxide as product. During combustion reaction a compound reacts with oxygen in order to yield oxides of elements present in the compound.

The general equation is given as:

$4M_3N_x+7xO_2\rightarrow 4xNO_2+6M_2O_x$

Hence, the correct answer is :X is nitrogen dioxide, and Y is a metal oxide.

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3 years ago

Which characteristic makes legumes a good food source for food-insecure populations?

vova2212 [387]

Legumes are much easier to grow than other plants, and are more adaptable.

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3 years ago

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