Answer: The correct option is A.
Explanation: Moles of Iron nail can be calculated by using the formula:
...(1)
Given mass of iron nail = 100 g
Molar mass of iron = 56 g/mol
Number of moles of iron nail = 1.79 moles
The chemical equation for the formation of rust if given by:
By Stoichiometry of the reaction,
4 moles of iron reacts with 3 moles of oxygen gas to produce 2 moles of rust.
So, 1.79 moles of iron will react with = 
= 1.3425 moles of oxygen gas.
For oxygen gas,
Molar mass = 32 g/mol
Mass of oxygen can be calculated by using equation 1, we get
Mass of oxygen gas = 43 grams
Hence, the correct option is a.
5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.
where,
- <em>c: specific heat capacity of gold</em> (0.129 J/g.°C)
- ΔT: change in the temperature
5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
You can learn more about heating here: brainly.com/question/1105305
Answer:
1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Explanation:
Given data:
mass of cadmium = 6.35 g
Number of atoms of aluminum as 6.35 g cadmium contain = ?
Solution:
Number of moles of cadmium = 6.35 g/ 112.4 g/mol
Number of moles of cadmium = 0.06 mol
Number of atoms of cadmium:
1 mole = 6.022×10²³ atoms of cadmium
0.06 mol × 6.022×10²³ atoms of cadmium/ 1mol
0.36×10²³ atoms of cadmium
Number of atoms of Al:
Number of atoms of Al = 0.36×10²³ atoms
1 mole = 6.022×10²³ atoms
0.36×10²³ atoms × 1 mol /6.022×10²³ atoms
0.06 moles
Mass of aluminum:
Number of moles = mass/molar mass
0.06 mol = m/ 27 g/mol
m = 0.06 mol ×27 g/mol
m = 1.62 g
Thus, 1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Answer:
There are 5 neutrons in beryllium
Answer:
Molecular mass
Explanation:
Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.
Thus,
Molecular mass = n × Empirical mass
Where, n is any positive number from 1, 2, 3...
Thus if the molecular mass is known, then we can find the value of n which results to molecular formula.
