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2 years ago

2. What is the mass of 5.33 x 10 moles of aluminum hydroxide?

1 answer:

8 0

<h3>Answer:</h3><h3>1865.5g</h3><h3>Explanation:</h3><h3 /><h2> first the chemical formular for ammonium hydroxide is NH4OH</h2><h3>its molarmass is given as N=14H=1O=16 </h3><h3> so we have 14 +1(2) +16+1 =35</h3><h2>also no of moles = mass / molarmass</h2><h3> we have 5.33×10 = mass/35 </h3><h2>therefore mass = 35 ×5.33×10 = 1865.5g</h2>

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3 years ago

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2 years ago

During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What

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3 years ago

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I hope it helps!

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3 years ago

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Read the paper more carefully if you don't understand it

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2 years ago

2. What is the mass of 5.33 x 10 moles of aluminum hydroxide?​

2. What is the mass of 5.33 x 10 moles of aluminum hydroxide?