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skelet666 [1.2K]
3 years ago
7

Is 0.21 rational or irrational

Mathematics
2 answers:
Tanya [424]3 years ago
3 0
A rational number can be made into a fraction
0.21 = 21/100....so it is rational
aalyn [17]3 years ago
3 0
It would be a rational number
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Cos A) 16/20 or 4/5
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Translate the algebraic expression below into a written expression.
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Its C

Step-by-step explanation:

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The length of a rectangular park is 3 feet shorter than times its width. If the length is 123 feet, what is the width of the par
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Answer:

Width is 120ft but may be different if the "times the width" information is given. Follow the same process.

Step-by-step explanation:

To solve the problem, write an expression that relates length and width using the information given to you. "The length of a rectangular park is 3 feet shorter than times its width" means that l = 3 + w. Since no number is given for "times its width" we disregard this portion. If you have the information then you would include it here l = 3 + _w.

So using the expression l = 3 + w, substitute l = 123. Then the width will be:

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123 = 3 + w

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3 years ago
Describe the difference between total surface area and lateral surface area
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Read 2 more answers
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
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