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UNO [17]
3 years ago
13

PLEASE HELP ASAP!!!!!!!!

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

a)f(o)=12

f(1)=0

f(12)=1320

c)x=1

Step-by-step explanation:

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HELP IVE GOT 5 MINS!!
faust18 [17]

Answer:

< A = 148°

Step-by-step explanation:

<A = <B → 6x - 2° = 4x + 48° → 2x = 50° → x = 25°

<A = 6(25°) - 2° = 150° - 2° = 148°

8 0
3 years ago
Use the box plots comparing the number of male puppies and number of female puppies attending doggy daycare each day for a month
dalvyx [7]
  1. The IQR for the males' data is 25.
  2. The difference between the median of the males' data and the female's data is 14.
  3. The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
  4. A reason for the outlier is that the number of dogs needing care increased.

<h3>What is the interquartile range?</h3>

The interquartile range for the males data is the difference between the third quartile and the first quartile.

IQR = third quartile - first quartile

25 - 0 = 25

Median = 20 - 6 = 14

An outlier is a number that is way smaller or way larger than that of other numbers in a data set.

To learn more about outliers, please check: brainly.com/question/27197311

#SPJ1

7 0
1 year ago
What is the average rate of change between hour 15 and hour 30
adell [148]

Answer:

5 hours

Step-by-step explanation:

there is no picture so i'm gonna just sya 5 because 5 + 15 is 30 .

5 0
3 years ago
1) Find the lump that must be deposited today to have a future value of $ 25,000 in 5 years if funds earn 6 % componded annually
Hoochie [10]

Answer: $ 18681.45

Step-by-step explanation:

Given: Future value : FV=\$25,000

The rate of interest : r=0.06

The number of time period : t=5

The formula to calculate the future value is given by :-

\text{Future value}=P(1+i)^n, where P is the initial amount deposited.

\Rightarrow\ 25000=P(1+0.06)^5\\\\\Rightarrow\ P=\dfrac{25000}{(1.06)^5}\\\\\Rightarrow\ P=18681.4543217\approx=18681.45

Hence, the lump that must be deposit today : $ 18681.45

4 0
3 years ago
Please answer this with explanation. Please I really am struggling. I will mark you brainalist. Please solve it Please
Hatshy [7]

Answer:

13, 11, 4, 16, 6, 22

Step-by-step explanation:

<em>Let the second digit be x and the last digit be y</em>

Given:

  • Data set: 13, x, 4, 16, 6, y
  • Mean = 12
  • y = 2x or x = 2y

The mean of the data is the average. The average can be calculated by determining the sum of the terms and dividing it by the total digits.

\implies \text{Mean of data:} \ \dfrac{13 + x + 4 + 16 + 6 + y}{6} = 12

Let us substitute the value of y (2x) in the data.

\implies \dfrac{13 + x + 4 + 16 + 6 + 2x}{6} = 12

Now, add all the terms in the data and simplify.

\implies \dfrac{39 + x +2x}{6} = 12

\implies \dfrac{39 + 3x}{6} = 12

Distribute the denominators and simplify.

\implies \dfrac{39}{6} + \dfrac{3x}{6}  = 12

\implies  \dfrac{13}{2} + \dfrac{x}{2}  = 12

\implies  6.5 + \dfrac{x}{2}  = 12

Subtract 6.5 both sides and simplify.

\implies  6.5 + \dfrac{x}{2}  - 6.5 = 12 - 6.5

\implies \dfrac{x}{2} = 5.5

Use cross multiplication and simplify.

\implies x= 5.5 \times 2

\implies  x= 11

To determine the value of "y", simply substitute the value of "x" into the expression that represents the value of "y".

\implies y = 2x

\implies y = 2(11)

\implies y = 22

When the x and y values are substituted in the data, we get;

  • ⇒ 13, 11, 4, 16, 6, 22

Therefore, the data is 13, 11, 4, 16, 6, 22.

8 0
2 years ago
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