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3 years ago

You spin a spinner with 5 sections: 1 blue (B) 1 purple (P), 1 red (R), 1 orange

Mathematics

2 answers:

baherus [9]3 years ago

8 0

Answer:

B. (B P R O G)

Step-by-step explanation:

this answer includes the whole population of the sample space

patriot [66]3 years ago

8 0

B is the answer (B,P,R,O,G)

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If men's heights are normally distributed with mean 68 and standard deviation 3.1 inches, and women's heights are normally distr

stira [4]

Answer:

the probability that the woman is taller than the man is 0.1423

Step-by-step explanation:

Given that :

the men's heights are normally distributed with mean $\mu$ 68

standard deviation $\sigma$ = 3.1

And

the women's heights are normally distributed with mean $\mu$ 65

standard deviation $\sigma$ = 2.8

We are to find the probability that the woman is taller than the man.

For woman now:

mean $\mu$ = 65

standard deviation $\sigma$ = 2.8

$P(x > 68 ) = 1 - p( x< 68)$

$\\ 1 -p \ P[(x - \mu ) / \sigma < (68-25)/ 2.8]$

= 1-P (z , 1.07)

Using z table,

= 1 - 0.8577

= 0.1423

Thus, the probability that the woman is taller than the man is 0.1423

6 0

3 years ago

Evaluate the following expression 1/3^2

NISA [10]

Answer:

1/9

Step-by-step explanation:

1/3*1/3=1/9

6 0

4 years ago

NEED HELP ASAP!! FILL IN THE BLANKS!! I'LL MARK YOU BRAINLIEST IF YOU ANSWER RIGHT!!!

amm1812

Answer: (x+8)^2 = 127

Step-by-step explanation:

4 0

3 years ago

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

The difference of the present ages of two sister in 5 yrs

Gekata [30.6K]

Answer:

4 and 9

Step-by-step explanation:

let their ages be x and x - 5, then in 4 years their ages will be

x + 4 and x - 5 + 4 = x - 1 , and the product is 104, thus

(x + 4)(x - 1) = 104 ← expand factors on left using FOIL

x² + 3x - 4 = 104 ( subtract 104 from both sides )

x² + 3x - 108 = 0 ← in standard form

(x + 12)(x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 12 = 0 ⇒ x = - 12

x - 9 = 0 ⇒ x = 9

However, x > 0 ⇒ x = 9

Thus

Their present ages are 9 and 9 - 5 = 4

4 0

3 years ago