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notka56 [123]
3 years ago
9

PLEASE HELP. Use the figure below to answer the question.

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer: A .  The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "

Step-by-step explanation:

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Simplify help me plss cuz I don’t find the answer
dusya [7]
32^(-1/5)

1/32^(1/5)

^1/5 means 5√32 = 2

so the answer is 1/2 or 0.5
6 0
4 years ago
Evaluate if x = 2.<br> 9x + 13<br> A) 5 <br> B) 18 <br> C) 24 <br> D) 31
Natasha2012 [34]
<span> if x = 2
9x + 13 = 9*2 + 13 = 18 + 13 = 31

</span><span>D) 31</span>
3 0
3 years ago
Can someone help me plz!!
a_sh-v [17]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
*Mastery Check. DO NOT ask for help. Find the area of the sector. Round your answer to the nearest tenth.
Juliette [100K]

The area of the sector is 472.6 ft²

<h3>Area of a Sector</h3>

For finding the area of the sector, you need apply the formula:

A=\pi r^2* \frac{\alpha }{360}, where:

r= radius

α= central angle

The question gives:

r= radius= 19 ft

α= central angle = 150°

Thus, the area of the sector will be:

A=\pi r^2* \frac{\alpha }{360}=\pi *19^2*\frac{150}{360} =472.6

Read more about the area of a sector here:

brainly.com/question/22972014

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3 0
2 years ago
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
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