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vlada-n [284]
3 years ago
7

Question: What is the equation of this trend line?

Mathematics
2 answers:
Fantom [35]3 years ago
4 0

Take 2 points (J,K)

  • (2,24)
  • (4,20)

\\ \tt\longmapsto m=\dfrac{20-24}{4-2}=\dfrac{4}{2}=2

Equation

\\ \tt\longmapsto K-24=2(J-2)

\\ \tt\longmapsto K-24=2J-4

\\ \tt\longmapsto K=2J+20

Yuki888 [10]3 years ago
3 0

Answer:

A trend line is a straight line that illustrates the points on a scatter plot.  

The equation of the trend line is: k = -2j + 24

Step-by-step explanation:

From the graph, we have the following points

(j, k) = (6, 12)(4, 16)

Start by calculating the slope

m = k2 - k1 / j2 - j1

So, we have:

m= 16 - 12 / 4 - 6

m = 4 / -2

m= -2

The equation is then calculated as:

k=m(j – j1) + k1

This gives:

k= -2(j - 6) +12

Expand

k= -2j + 12 +12

k= -2j + 24

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(1)  Null Hypothesis, H_0 : \mu_1 = \mu_2

    Alternate Hypothesis, H_1 : \mu_1\neq \mu_2

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let \mu_1 = mean annual family income for 12 people making inquiries at the first development

\mu_2 = mean annual family income for 24 people making inquiries at the second development

s_1 = standard deviation of annual family income for 12 people making inquiries at the first development

s_2 = standard deviation of annual family income for 24 people making inquiries at the second development

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n_2 = sample of people of second development i.e. 24

(1) Null Hypothesis, H_0 : \mu_1 = \mu_2  {population means are same}

  Alternate Hypothesis, H_1 : \mu_1\neq \mu_2  {population means are different}

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(2) The test statistics is given by;

                      \frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where,  X_1bar = Sample mean income of people at first development

                        = $153,000

X_2bar = Sample mean income of people at second development = $171,000  

s_1 = $42,000  and   s_2 = $30,000

   s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2}} =  \sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2}  }{12+24-2}} = 34344.30

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(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

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