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3 years ago

Question: What is the equation of this trend line?

Mathematics

2 answers:

Fantom [35]3 years ago

4 0

Take 2 points (J,K)

(2,24)
(4,20)

$\\ \tt\longmapsto m=\dfrac{20-24}{4-2}=\dfrac{4}{2}=2$

Equation

$\\ \tt\longmapsto K-24=2(J-2)$

$\\ \tt\longmapsto K-24=2J-4$

$\\ \tt\longmapsto K=2J+20$

Yuki888 [10]3 years ago

3 0

Answer:

A trend line is a straight line that illustrates the points on a scatter plot.

The equation of the trend line is: k = -2j + 24

Step-by-step explanation:

From the graph, we have the following points

(j, k) = (6, 12)(4, 16)

Start by calculating the slope

m = k2 - k1 / j2 - j1

So, we have:

m= 16 - 12 / 4 - 6

m = 4 / -2

m= -2

The equation is then calculated as:

k=m(j – j1) + k1

This gives:

k= -2(j - 6) +12

Expand

k= -2j + 12 +12

k= -2j + 24

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28 students in the class 75% pass how many students pass

SashulF [63]

Answer:

21 students pass

Step-by-step explanation:

Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction $\frac{75}{100}$ (which is 75% represented as a fraction).

$\frac{X}{28} = \frac{75}{100}$

The fraction $\frac{75}{100}$ can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with $\frac{3}{4}$ .

$\frac{X}{28} = \frac{3}{4}$

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

$\frac{X}{28} * 28 * 4 = \frac{3}{4} * 4 * 28$

The denominators cancel out leaving you with a simple equation to simplify.

$4* X = 3 * 28$

$4X = 84$

Finally, divide both sides by four in order to isolate the variable.

$\frac{4X}{4} = \frac{84}{4}$

X = 21.

5 0

3 years ago

You are given a list of students names and their test scores. Design a pseudocode that does the following:(a) Calculates the ave

Rashid [163]

Answer:

List_of_students = {}; //Structure array that contains the scores of students and Names

Number_of_students = size(List_of_students);

Average_score ; //Variable Stores average score

Below_Average = []; //That is initially filled with zeros

Highest_score ; //Initialize variable to store highest score

for ( i = 0 ; i < Number_of_students; i = i + 1)

{

Average_score = Average_score + List_of_students(i);

if ( i = 15)

{

Average_score = Average_score / Number_of_students;

}

for ( j = 0; j < Number_of_students ; i = i + 1)

{

if ( List_of_students(j) < Average_score)

{

print( "student %name got %score , List_of_students(j), List_of_students(j) )

}

Compare_Score = 0; //Variable to compare score

for ( k = 0; K < Number_of_students; k = k+1)

{

if ( List_of_students(k) => Compare_Score)

{

Compare_Score = List_of_students(k);

}

Highest_Score = Compare_Score;

Step-by-step explanation:

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GarryVolchara [31]

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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