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DanielleElmas [232]

2 years ago

5

Huda purchased 200 beads for AED 48 to make necklace. if she needs to buy 25 more beads, how much will she pay if she is charged

the same rate?

1 answer:

Natasha_Volkova [10]2 years ago

3 0

She would need to spend 6 more. To find this answer, you divide 48 by 200 to see how much each bead costs, and then you multiply that amount by 25.

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What is the distance between (-3,1) and (-2,-1) in units

Nastasia [14]

Answer:

Here is the graph I made, starting from (-3,1) to (-2,-1) it goes down 2 units and over 1 unit.

6 0

2 years ago

Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

3 0

3 years ago

4 students from a class of 15 are going to be chosen to be on the dance committee. Find the number of different 4-person committ

Andrej [43]

We know that
The formula for combinations is
C=n!/[(n-r)!*r!]
where
n is the total number of objects you choose from
r is the number that you choose to arrange

in this problem
n=15 students
r=4 students
C=15!/[(15-4)!*4!]-----> C=15!/[11!*4!]---> (15*14*13*12*11!)/(11!*4*3*2*1)
C=(15*14*13*12)/(24)----->C=1365

the answer is
1365

7 0

2 years ago

Read 2 more answers

What is 0.000025(800)^2 - 0.04(800) +40..?

Scilla [17]

Answer:

24

Step-by-step explanation:

6 0

2 years ago

1.) Determine whether each number is irrational or rational.

nalin [4]

Answer:

1/3 is rational its nonterminating but it repeats

6.99999 rational its nonterminating and it repeats also

7.48331 is irrational because its non terminnating and it does not repeat

Step-by-step explanation:

8 0

2 years ago