Answer:
w=2 w = -9
Step-by-step explanation:
w^2 + 7w - 18 = 0
We can factor this equation
What 2 numbers multiply to -18 and add to 7
9*-2 = -18
9+-2 = 7
(w-2) (w+9) = 0
Using the zero product property
w-2 = 0 w+9 =0
w=2 w = -9
Answer:
The correct answer is y = 9
Step-by-step explanation:
It is given that,
12/(4y + 6) = 2/7
<u>To find the value of y</u>
12/(4y + 6) = 2/7
By cross multiplying,
12 * 7 = 2 * (4y + 6 )
84 = 8y + 12
8y + 12 = 84
8y = 84 - 12
8y = 72
y = 72/8 = 9
y = 9
Therefore by solving the given expression we get the value of y = 9
Hello!
To solve algebraic equations, we need to first, simplify the common terms, and secondly use SADMEP. SADMEP is strictly used to solve algebraic equations, and is used like PEMDAS. SADMEP is an acronym for subtract, addition, division, multiplication, exponents, and parentheses.
25 - 4x = 15 - 3x + 1 - x (simplify the common terms)
25 - 4x = 16 - 4x (subtract 16 from both sides)
9 - 4x = -4x (add 4x to both sides)
9 = 0 → This means that there is no solutions.
Therefore, this equation has no solutions, which are contradictions because those are the equations with no solution.
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
F(t) = -5t^2 + 20t + 60
-5(t^2 - 4t - 12)
-5(t + 2) (t - 6)
t = -2 or t = 6
6 seconds