Answer
is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.
V(N₂O) = 8.4 L.
V(N₂O) =
n(N₂O) · Vm.
Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.
n(N₂O) = 8.4 L ÷ 22.4 L/mol.
n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>
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VSEPR theory (known as Valence Shell Electron Pair Repulsion ) endeavors to explain/predict the shape and geometry of molecules. The theory postulates that atoms in a molecule take a position in space (within the molecule) that reduces the repulsion of the individual atom’s electron clouds so the molecule can achieve the most stable state.
