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STALIN [3.7K]
2 years ago
7

Helppppppppppppppppppppppppppppppppppppppppppppppppp

Chemistry
2 answers:
Ierofanga [76]2 years ago
7 0

Answer:

the answer is A

Explanation:

Anit [1.1K]2 years ago
6 0

Answer:   it is a

Explanation:

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How many grams do 6.534e+24 molecules of phosphoric acid weigh?
fredd [130]

Answer:

1,063 grams H₃PO₄

Explanation:

To find the mass of phosphoric acid (H₃PO₄), you should (1) convert molecules to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass from periodic table).

Molar Mass (H₃PO₄): 3(1.008 g/mol) + 30.974 g/mol + 4(15.998 g/mol)

Molar Mas (H₃PO₄): 97.99 g/mol

6.534 x 10²⁴ molecules H₃PO₄                       1 mole                         97.99 g
---------------------------------------------  x  -------------------------------------  x  --------------
                                                            6.022 x 10²³ molecules          1 mole

= 1,063 grams H₃PO₄

3 0
1 year ago
What do all electrolytes have in common?
Lerok [7]
Your answer would be they have mobile ions in solution.
7 0
2 years ago
What is chemistry? ​
kirill [66]

Answer:the branch of science which examines the material of the universe and changes that these materials undergo

Chemistry deals with composition,structure,properties of matter and changes that these materials undergo

3 0
3 years ago
If a runner maintains a constant speed of 12 miles an hour how long will it take to complete a half marathon race of 13.1 miles?
Nutka1998 [239]
At 12 mph, how long does it take to go 13.1 miles?

We know that distance = rate * time
So we know that 13.1 = 12 * time
We can now see that time = 13.1/12 = 1.092 (hours)
That's approximately 1 hour and .092*60=5.52 minutes.
3 0
2 years ago
Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un
maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0
3 years ago
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