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lesya [120]
3 years ago
15

Power is the rate at which energy is?

Chemistry
1 answer:
Mrrafil [7]3 years ago
6 0
In physics, power is the rate of doing work. It is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. In the SI system, the unit of power is the joule per second (J/s), known as the watt in honour of James Watt, the eighteenth-century developer of the steam engine.
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mel-nik [20]

Answer:

Usually, the cells are round, elongated or spherical. There are also some cells which are long and pointed on both the ends. Such cells exhibit spindle shape. In some cases, the cells are very long.

Explanation:

Hope I helped! Brainliest plz!

3 0
3 years ago
For the reaction c + 2h2 → ch4, how many moles of hydrogen are required to produce 10 moles of methane, ch4?
r-ruslan [8.4K]
                                                 C+2H2 -------> CH4   
from reaction                              2 mol           1 mol
from the problem                       x mol           10 mol

x=2*10/1 = 20 mol

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3 years ago
If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus
timofeeve [1]

Answer:

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

Explanation:

Let the volume of the helium gas be = V

Time taken by the helium gas = t = 1.34 min

Effusion rate of helium gas = R=\frac{V}{1.34 min}

If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

R'=\frac{V}{t'}

Using Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Molar mass of helium gas = M = 4 g/mol

Molar mass of ammonia gas = M' = 17 g/mol

\frac{R}{R'}=\sqrt{\frac{M'}{M}}

\frac{\frac{V}{1.34 min}}{\frac{V}{t'}}=\sqrt{\frac{17 g/mol}{4 g/mol}}

t'=1.34 min\times \sqrt{\frac{17 g/mol}{4 g/mol}}=2.76 min

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

8 0
3 years ago
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Serjik [45]

The answer is A. an ore.

8 0
3 years ago
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How many liters of oxygen gas, at standard temperature and pressure, will react with 35.4 grams of calcium metal? Show all of th
maks197457 [2]
9.9 liters is your answer

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4 years ago
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