Nitrous oxide (n2o), or laughing gas, is commonly used as an anesthetic in dentistry and surgery. how many moles are present in 8.4 liters of nitrous oxide at stp?
1 answer:
Answer
is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.
V(N₂O) = 8.4 L.
V(N₂O) =
n(N₂O) · Vm.
Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.
n(N₂O) = 8.4 L ÷ 22.4 L/mol.
n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>
You might be interested in
The first one is abundant
Do you have a picture of the graph?
The common name is laundry bleach Hope this helps
Answer:
Explanation:
(a) Balanced equation
3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O
(b) Moles of NaOH
(c) Moles of H₃PO₄
The molar ratio is 1 mol H₃PO₄:3 mol NaOH.
(d) Molar concentration of H₃PO₄
K shows a decrease in disorder (AS = -120.7 J/(mol-K)) during an exothermic reaction (AH' = -136.9 kJ/mol). Determine whether the reaction is spontaneous or ...