Answer:
176
Step-by-step explanation:
11x11=121
12x11=132
9=20-11
16-9=7
11x16=176
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Answer:
Seven numbers.
Step-by-step explanation:
Finding the numbers, which are equal to the sum of two odd number and it has to be single digit number.
Lets look into numbers which are odd and single digit.
1 = 
∴ Sum of the number is 
3 = 
∴ Sum of above number is 
5 = 
∴ Sum of above number is 
7= 
∴ Sum of above number is 
Now, accumlating numbers which are fullfiling the criteria, however, making sure no number should get repeated.
∴ Numbers are: 
Hence, there are total 7 numbers, which are equal to the sum of two odd, one-digit numbers.
<h2>
Step-by-step explanation:</h2>
As per the question,
Let a be any positive integer and b = 4.
According to Euclid division lemma , a = 4q + r
where 0 ≤ r < b.
Thus,
r = 0, 1, 2, 3
Since, a is an odd integer, and
The only valid value of r = 1 and 3
So a = 4q + 1 or 4q + 3
<u>Case 1 :-</u> When a = 4q + 1
On squaring both sides, we get
a² = (4q + 1)²
= 16q² + 8q + 1
= 8(2q² + q) + 1
= 8m + 1 , where m = 2q² + q
<u>Case 2 :-</u> when a = 4q + 3
On squaring both sides, we get
a² = (4q + 3)²
= 16q² + 24q + 9
= 8 (2q² + 3q + 1) + 1
= 8m +1, where m = 2q² + 3q +1
Now,
<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>
Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.
Hence , it is clear that square of an odd positive is in form of 8m +1
C) sss similarity
because each side as a partner with half of its value
8in-4in
6in-3in
4in-2in