Answer:
The gradient of the straight line that passes through (2, 6) and (6, 12) is
.
Step-by-step explanation:
Mathematically speaking, lines are represented by following first-order polynomials of the form:
(1)
Where:
- Independent variable.
- Dependent variable.
- Slope.
- Intercept.
The gradient of the function is represented by the first derivative of the function:

Then, we conclude that the gradient of the staight line is the slope. According to Euclidean Geometry, a line can be form after knowing the locations of two distinct points on plane. By definition of secant line, we calculate the slope:
(2)
Where:
,
- Coordinates of point A.
,
- Coordinates of point B.
If we know that
and
, then the gradient of the straight line is:



The gradient of the straight line that passes through (2, 6) and (6, 12) is
.
<h2>-0.71 is it i think so i dk </h2>
145 will work. It is an odd number and is greater than 142 and is less than 156
142 < 145 < 156
Other numbers such as 143, 147, 149,151,153, 155 will work.
Answer:
-19561285.5554
Step-by-step explanation: