Answer:
WY= 25
XY= 23
VZ=36
so,
WY/XY = YZ/VZ
25/23 = YZ/25 (then do cross multiply)
25×25 = 23 × YZ
625= 23 × YZ
625/23= YZ
27,17= YZ
#i'm indonesian
#hope it helps.
Answer:
c
Step-by-step explanation:
The general form of the equation is <span>acot (bx−c)+d</span><span> to find the variables used to find the amplitude, period, phase shift, and vertical shift where </span><span>a=1, </span><span>b=</span><span>π/4, </span><span>c=0 and </span><span>d=0
Period is pi/b or equal to 4.
The vertical asymptote is 4pi n where n is integer.
Attached is the sketch of the graph
</span>
we are given
(a)
we can plug t=0
so, the height above the ground when the object is launched is 60 meter......Answer
(b)
we can set s(t)=0
and then we can solve for t
we can use quadratic formula
we get
..........Answer
(c)
we can find vertex
t=2.040816
now, we can plug it back
so, the maximum height is 80.408meter.........Answer