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3 years ago

How many grams of hydrogen gas would be produced from the use of 9.5 miles of aluminum?

Chemistry

1 answer:

pishuonlain [190]3 years ago

5 0

Answer:

28.5g of H2

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2Al + 6HCl —> 2AlCl3 + 3H2

From the balanced equation,

2moles of Al produced 3moles of H2.

Therefore, 9.5 moles of Al will produce = (9.5x3)/2 = 14.25moles of H2.

Now let us convert 14.25moles of H2 to grams as illustrated below:

Molar Mass of H2 = 2x1 = 2g/mol

Number of mole H2 = 14.25moles

Mass of H2 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of H2 = 14.25 x 2

Mass of H2 = 28.5g

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How many oxygen atoms are contained in 2.74 g of Al2(SO4)3?

abruzzese [7]

Answer:

5.79 × 10^23 Oxygen atoms

Explanation:

Number of Oxygen atom in the compound = 4×3 = 12

Molar mass of Al2(SO4)3 = 342 g/mol.

No of mole = mass/molar mass = 2.74/342 = 8.01×10^-03 mole

2.74g of Al2(SO4)3 × 1 mole of Al2 (SO4)3 / 342g of Al2 (SO4)3 * 12 mole of Oxygen/ 1mole of Al(SO4)3 * 6.02×10^23 Oxygen atom/ 1 mole of Oxygen

= 5.79×10^23 Oxygen atoms

3 0

3 years ago

Read 2 more answers

A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is

Charra [1.4K]

Answer:

$[H^{+}] = 0.761 \frac{mol}{L}$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

$pH = 0.119$

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

$n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L) \\ n_{H^{+} } from HNO_{3} = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)$

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

$n_{H^{+} } from HCl = (5.00)(0.093)$

$n_{H^{+} } from HCl = 0.465 mol$

$n_{H^{+} } from HNO_{3} = (8.00)(0.037)$

$n_{H^{+} } from HNO_{3} = 0.296 mol$

$n_{H^{+}(total) } = 0.296 + 0.465$

$n_{H^{+}(total) } = 0.761 mol$

For molar concentration of hydrogen ions:

$[H^{+}] = \frac{n_{H^{+}}(mol)}{V(L)}$

$[H^{+}] = \frac{0.761}{1.00}$

$[H^{+}] = 0.761 \frac{mol}{L}$

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

$K_{w} = [H^{+} ][OH^{-} ]$

$[OH^{-}]=\frac{Kw}{[H^{+}] }$

$[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

The pH of the solution can be measured by the following formula:

$pH = -log[H^{+} ]$

$pH = -log(0.761)$

$pH = 0.119$

5 0

3 years ago

Which material is very strong and tough but shows very little elongation as it absorbs energy?

natita [175]

Kevlar would be the answer!! enjoy the rest of your day broskies!!!

7 0

3 years ago

Which element has their valence electron farthest from the nucleus?

Iteru [2.4K]

The answer is Rubidium (Rb)

4 0

3 years ago

Student have a receipt which calls for 1.15 lb of flour, but, of course, in France you will need to purchase flour in kilograms.

Verizon [17]

0.52164 kg of Flour

<u>Explanation:</u>

We have to convert lb (pounds) kg (kilograms), by using the conversion unit,

1 lb = 0.4536 kg

So to convert 1.15 lb into kg, we have to multiply 1.15 by 0.4536.

$1.15 \times 0.4536$ = 0.52164 kg of Flour

So the receipt calls for 0.52164 kg of Flour.

5 0

4 years ago