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3 years ago

How many grams of hydrogen gas would be produced from the use of 9.5 miles of aluminum?

Chemistry

1 answer:

pishuonlain [190]3 years ago

5 0

Answer:

28.5g of H2

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2Al + 6HCl —> 2AlCl3 + 3H2

From the balanced equation,

2moles of Al produced 3moles of H2.

Therefore, 9.5 moles of Al will produce = (9.5x3)/2 = 14.25moles of H2.

Now let us convert 14.25moles of H2 to grams as illustrated below:

Molar Mass of H2 = 2x1 = 2g/mol

Number of mole H2 = 14.25moles

Mass of H2 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of H2 = 14.25 x 2

Mass of H2 = 28.5g

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The products of a chemical reaction have different properties than the reactants.

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Answer:

Explanation:

The products of a chemical reaction have different properties than the reactant because they underwent a chemical change by definition of a chemical reaction. The products are new combinations atoms forming different molecules.

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2 years ago

Converting carbon to nitrogen by increasing the number of protons from 6 to 7 and decreasing the number of neutrons from 8 to 7

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3 years ago

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Hence the correct answer B) Theoretical yield

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3 years ago

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A solution of barium nitrate has 61.2g of barium nitrate in 1 liter of solution. How many mg of barium are there in 7.5 quarts

Nuetrik [128]

Answer:

220.44g Ba²⁺ ions in solution

Explanation:

Given parameters:

Mass of barium nitrate = 61.2g

Volume of solution = 1 liter

Unkown:

Mass of barium in 7.5quarts of solution?

Solution

We must first convert quarts to its liter equivalence:

1 quarts = 0.95 liter

7.5 quarts = 0.95 x 7.5; 7.125liter

Now, let us find the mass of barium nitrate in a solution of 7.125liter:

Given:

1 liter of solution contains 61.2g of barium nitrate:

7.125 liter will contain 7.125 x 61.2 = 436.05g of barium nitrate.

The formula of the compound is Ba(NO₃)₂:

In solution we have Ba²⁺ + NO₃⁻

Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻

Number of moles of Ba(NO₃)₂ = $\frac{mass of Ba(NO₃)₂}{Molar mass of Ba(NO₃)₂}$

Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol

Number of moles of Ba(NO₃)₂ = $\frac{436.05}{271}$ = 1.609mole

1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution

therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution

Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions x molar mass of Ba²⁺ ions

Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g

3 0

3 years ago

The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

Rina8888 [55]

<u>Answer:</u> The expression of $K_b$ is written below.

<u>Explanation:</u>

We are given a chemical compound which is trimethylamine that acts as a weak base when dissolved in water.

It accepts a proton from the water to form trimethylammonium ion and hydroxide ion.

The chemical equation for the reaction of trimethylamine in water follows:

$(CH_3)_3N+H_2O\rightleftharpoons (CH_3)_3NH^++OH^-$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

Hence, the expression of $K_b$ is written above.

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3 years ago