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3 years ago

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How many dozens of copper atoms are in a penny.?

2 answers:

77julia77 [94]3 years ago

7 0

$\boxed{2.5 \times {{10}^{21}}{\text{ dozen}}}$ ofcopper atoms are present in a penny.

Further Explanation:

Atom is the smallest particle and is building block of matter. It comprises of a central part called atomic nucleus that is surrounded by electrons revolving in circular orbits. Atomic nucleus consists of protons and electrons while electronsare present around it. Electrons are negatively charged particles, protons are positively charged particles and neutrons have no charge.

To calculate:

Number of copper atoms in 1 penny

One penny of pure copper consists of $3.0 \times {10^{22}}{\text{ atoms}}$ of copper. A dozen is one of the units of measurement. 12 quantities of anything make up one dozen. So one dozen is equivalent to 12 quantities. Such quantities can be atoms, molecules, ions, formula units and many other things as are required according to the problem to be solved.

Since 12 atoms are present in one dozen, number of dozen in $3.0 \times {10^{22}}{\text{ atoms}}$ of copper can be calculated as follows:

$\begin{aligned}{\text{Number of dozen}} &= \left( {3.0 \times {{10}^{22}}{\text{ atoms}}} \right)\left( {\frac{{1{\text{ dozen}}}}{{12{\text{ atoms}}}}} \right) \\&= 2.5 \times {10^{21}}{\text{ dozen}} \\\end{aligned}$

Learn more:

How many moles of Cl are present in 8 moles of ${\text{CC}}{{\text{l}}_4}$ ? brainly.com/question/3064603
Calculate the moles of ions in HCl solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: penny, copper atoms, 3.0*10^22 atoms, dozen, 12 quantities, number of copper atoms, pure copper, atoms, ions, molecules, protons, electrons, neutrons, negatively charged, positively charged, no charge.

NikAS [45]3 years ago

3 0

There is 2.5 .10²¹ dozen of copper atoms are in a penny

<h3>Further explanation </h3>

Stochiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example the substance level or molecular formula of hydrate.

A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) with

While the number of moles can also be obtained by dividing the mass (in grams) with

$\large{\boxed{\bold{mole\:=\:\frac{grams}{ the\:relative\:mass\:of\:elements\:or\:the relative\:mass\:of\:molecules} }}}$

The complete question must be :

A pure copper penny contains approximately 3.0. 10²² copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 . 10²³

Use these definitions to determine the following:

How many dozens of copper atoms are in a penny.

Because there is 12 atoms for 1 dozen then , in a penny

3.0. 10²² : 12 atoms = 2.5 .10²¹ dozen

<h3>Learn more </h3>

Avogadro's number

brainly.com/question/859564

carbon atoms in 1.50 g of butane

brainly.com/question/5122019

a mole and Avogadro’s number

brainly.com/question/1445383

Keywords: mole, Avogadro’s number, a penny, copper, atoms

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pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = $pK_a=9.31$

First we have to calculate the moles of HCN and NaCN.

$\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole$

and,

$\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole$

The balanced chemical reaction is:

$HCN+NaOH\rightarrow NaCN+H_2O$

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At eqm. (0.1116-0.0461) 0 (0.08978+0.0461)

0.0655 0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

Now put all the given values in this expression, we get:

$pH=9.31+\log (\frac{0.1359}{0.0655})$

$pH=9.63$

Therefore, the pH of the solution is, 9.63

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3 years ago

L avanzar hacia la derecha por el período 5, el tamaño atómico, la energía de ionización y los electrones de valencia: A. dismin

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Answer:

Al avanzar hacia la derecha por el período 5, el tamaño atómico, la energía de ionización y los electrones de valencia: A. disminuye, aumenta y aumentan, respectivamente.

Explanation:

El radio atómico representa la distancia que existe entre el núcleo y la capa de valencia, es decir la más externa. Por medio del radio atómico es posible determinar el tamaño del átomo. En un período el tamaño atómico disminuye de izquierda a derecha pues en este sentido aumenta el número atómico aumentando la carga nuclear mientras que el efecto pantalla y el número de niveles permanecen constantes. En otras palabras, disminuye de izquierda a derecha debido a la atracción que ejerce el núcleo sobre los electrones de los orbitales más externos, disminuyendo así la distancia núcleo-electrón.

<u><em>Al avanzar hacia la derecha por el período 5, el tamaño atómico disminuye.</em></u>

La energía de ionización es la necesaria para remover un electrón a un átomo en estado gaseoso. Mientras más lejos del núcleo esté el electrón, es más fácil removerlo porque se necesita menos energía. Al aumentar el número atómico de los elementos de un mismo período, se incrementa la atracción nuclear sobre el electrón más externo, ya que disminuye el radio atómico y aumenta la carga nuclear efectiva sobre él. Entonces en un período, al aumentar el número atómico, la energía de ionización aumenta.

<u><em>Entonces, al avanzar hacia la derecha por el período 5, la energía de ionización y los electrones de valencia aumenta.</em></u>

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En cada período aparecen los elementos cuyo último nivel de su configuración electrónica coincide con el número del período, ordenados por orden creciente de número atómico. Por ejemplo, el período 3 incluye los elementos cuyos electrones más externos están en el nivel 3.

Los electrones de valencia aumentan en número a medida que se avanza en un período.

<u><em> Entonces, al avanzar hacia la derecha por el período 5, los electrones de valencia aumentan.</em></u>

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