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3 years ago

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How many dozens of copper atoms are in a penny.?

2 answers:

77julia77 [94]3 years ago

7 0

$\boxed{2.5 \times {{10}^{21}}{\text{ dozen}}}$ ofcopper atoms are present in a penny.

Further Explanation:

Atom is the smallest particle and is building block of matter. It comprises of a central part called atomic nucleus that is surrounded by electrons revolving in circular orbits. Atomic nucleus consists of protons and electrons while electronsare present around it. Electrons are negatively charged particles, protons are positively charged particles and neutrons have no charge.

To calculate:

Number of copper atoms in 1 penny

One penny of pure copper consists of $3.0 \times {10^{22}}{\text{ atoms}}$ of copper. A dozen is one of the units of measurement. 12 quantities of anything make up one dozen. So one dozen is equivalent to 12 quantities. Such quantities can be atoms, molecules, ions, formula units and many other things as are required according to the problem to be solved.

Since 12 atoms are present in one dozen, number of dozen in $3.0 \times {10^{22}}{\text{ atoms}}$ of copper can be calculated as follows:

$\begin{aligned}{\text{Number of dozen}} &= \left( {3.0 \times {{10}^{22}}{\text{ atoms}}} \right)\left( {\frac{{1{\text{ dozen}}}}{{12{\text{ atoms}}}}} \right) \\&= 2.5 \times {10^{21}}{\text{ dozen}} \\\end{aligned}$

Learn more:

How many moles of Cl are present in 8 moles of ${\text{CC}}{{\text{l}}_4}$ ? brainly.com/question/3064603
Calculate the moles of ions in HCl solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: penny, copper atoms, 3.0*10^22 atoms, dozen, 12 quantities, number of copper atoms, pure copper, atoms, ions, molecules, protons, electrons, neutrons, negatively charged, positively charged, no charge.

NikAS [45]3 years ago

3 0

There is 2.5 .10²¹ dozen of copper atoms are in a penny

<h3>Further explanation </h3>

Stochiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example the substance level or molecular formula of hydrate.

A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) with

While the number of moles can also be obtained by dividing the mass (in grams) with

$\large{\boxed{\bold{mole\:=\:\frac{grams}{ the\:relative\:mass\:of\:elements\:or\:the relative\:mass\:of\:molecules} }}}$

The complete question must be :

A pure copper penny contains approximately 3.0. 10²² copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 . 10²³

Use these definitions to determine the following:

How many dozens of copper atoms are in a penny.

Because there is 12 atoms for 1 dozen then , in a penny

3.0. 10²² : 12 atoms = 2.5 .10²¹ dozen

<h3>Learn more </h3>

Avogadro's number

brainly.com/question/859564

carbon atoms in 1.50 g of butane

brainly.com/question/5122019

a mole and Avogadro’s number

brainly.com/question/1445383

Keywords: mole, Avogadro’s number, a penny, copper, atoms

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Consider the following reaction. Zn(s) 2agno3(aq) --> 2ag(s) zn(no3)2(aq)when 16. 2 g of silver was produced, _____ mole(s) o

Crazy boy [7]

The required amount of silver nitrate to produce 16.2g of silver is 25.48 grams.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

W = given mass
M = molar mass

Moles of silver = 16.2g / 107.8g/mol = 0.15mol

From the stoichiometry of the given reaction it is clear that, same moles of silver nitrate is required to produce same moles of silver. So 0.15 moles of silver nitrate is required.

Mass of silver nitrate = (0.15mol)(169.87g/mol) = 25.48g

Hence required mass of silver nitrate is 25.48g.

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5 0

2 years ago

How many moles of water are produced if 5.43 mol PbO2 are consumed?<br><br> ANSWER: 10.9

Arada [10]

Answer: 10.9 mol.

Explanation:

To understand how to solve this problem, we must mention the reaction equation where water produced from PbO₂.

Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O

Now, it is a stichiometric oriented problem, that 1 mole of PbO₂ produces 2 moles of H₂O.

Using cross multiplication:

1.0 mole of PbO₂ → 2.0 moles of H₂O

5.43 moles of PbO₂ → ??? moles of water

The moles of water produced = (5.43 x 2.0) = 10.86 moles ≅ 10.9 moles.

4 0

4 years ago

Read 2 more answers

In another experiment, a 0.150 M BF4^-(aq) solution is prepared by dissolving NaBF4(s) in distilled water. The BF4^-(aq) ions in

Ilia_Sergeevich [38]

Answer:

A) Forward rate = 1.1934 × 10^(-4) M/min

B) I disagree with the claim

Explanation:

A) We are told that [HF] reaches a constant value of 0.0174 M at equilibrium.

The reversible reaction given to us is;

BF4-(aq) +H20(l) → BF3OH-(aq) + HF(aq)

From this, we can see that the stoichiometric ratio is 1:1:1:1

Thus, concentration of [BF4-] is now;

[BF4-] = 0.150 - 0.0174

[BF4-] = 0.1326 M

From the rate law, we are told the forward rate is kf [BF4-].

We are given Kf = 9.00 × 10^(-4) /min

Thus;

Forward rate = 9.00 × 10^(-4) /min × (0.1326M)

Forward rate = 1.1934 × 10^(-4) M/min

(B) The student claims that the initial rate of the reverse reaction is equal to zero can't be true because at equilibrium, rates for the forward and reverse reactions are usually equal.

Thus, I disagree with the claim.

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3 years ago

What ion does a base increase

cricket20 [7]

OH- is the ion that increases the concentration of a base

8 0

3 years ago

How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?

Ksenya-84 [330]

Answer:

a. Approximately $1.3\; \rm mL$ .

b. Approximately $7.2\; \rm mL$ .

Explanation:

The unit of concentration " $\rm M$ " is equivalent to " $\rm mol \cdot L^{-1}$ ", which means "moles per liter."

However, the volume of both solutions were given in mililiters $\rm mL$ . Convert these volumes to liters:

$\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L$ .

$\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L$ .

In a solution of volume $V$ where the concentration of a solute is $c$ , there would be $c \cdot V$ (moles of) formula units of this solute.

Calculate the number of moles of $\rm NaCl$ formula units in each of the two solutions:

Solution in a.:

$n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol$ .

Solution in b.:

$n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol$ .

What volume of that $3.4\; \rm M$ (same as $3.4 \; \rm mol \cdot L^{-1}$ ) $\rm NaCl$ solution would contain that many

For the solution in a.:

$\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL$ .

Similarly, for the solution in b.:

$\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL$ .

8 0

3 years ago