Answer:
1.)
2.)
3.)
4.)
5.)
6.)
Step-by-step explanation:
I did 6 problems for you. You can now do the other 4 problems and see how I did it. You need to have the same denominator and the add the fractions together.
. The mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days. Suppose that the incubation ti
mes are approximately normally distributed with a standard deviation of 1 day. Complete parts (a) through(e) below.
(a) Draw a normal model that describes egg incubation times of these fertilized eggs.
(b) Find and interpret the probability that a randomly selected fertilized egg hatches in less than 23 days.
The probability that a randomly selected fertilized egg hatches in less than 23 days is _?__. (Round to four decimal places asneeded.)
(a) Draw a normal model that describes egg incubation times of these fertilized eggs.
(b) Find and interpret the probability that a randomly selected fertilized egg hatches in less than 23 days.
The probability that a randomly selected fertilized egg hatches in less than 23 days is _?__. (Round to four decimal places asneeded.)
1 answer:
Answer:
Step-by-step explanation:
Given that the mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days.
Let X be the incubation time for a type of fertilized egg kept at a certain temperature is 25 days.
X is N(25, 1)
a) Normal curve is in the attached file
b) the probability that a randomly selected fertilized egg hatches in less than 23 days
=
we convert x into Z score and use std normal distn table to find probability
i.e. we can say only 2.5% proportion will hatch in less than 23 days.
You might be interested in
Answer:
When do you hit the water?
1.075 seconds after you jump.
What is your maximum height?
the maximum height is 12.5626 ft
Step-by-step explanation:
The equation:
h(t) = -16*t^2 + 6*t + 12
Is the height as a function of time.
We know that the initial height is the height when t = 0s
h(0s) = 12
and we know that the diving board is 12 foot tall.
Then the zero in h(t)
h(t) = 0
Represents the surface of the water.
When do you hit the water?
Here we just need to find the value of t such that:
h(t) = 0 = -16*t^2 + 6*t + 12
Using the Bhaskara's formula, we get:
Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)
The positive solution is:
t = (-6 - 28.4)/-32 = 1.075
So you hit the water 1.075 seconds after you jump.
What is your maximum height?
The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.
We know that the vertex of a general quadratic:
a*x^2 + b*x + c
is at
x = -b/2a
Then in the case of our equation:
h(t) = -16*t^2 + 6*t + 12
The vertex is at:
t = -6/(2*-16) = 6/32 = 0.1875
Evaluating the height equation in that time will give us the maximum height, which is:
h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626
And the height is in feet, then the maximum height is 12.5626 ft
