The way to do this is to set up a 30 degree angle in a coordinate plane in the first quadrant. I say the first quadrant since the first quadrant goes from 0 to 90 degrees and 30 falls right in that interval. Using the positive x-axis as the initial ray of the 30 degree angle and the terminal ray of the angle as the hypotenuse of a right triangle, if we drop a height from the end of the terminal ray to the x-axis we have formed said right triangle. The angle at the origin is the 30 degree angle. According to the Pythagorean triple for a 30-60-90 triangle, the side across from the 30 degree angle measures 1, which is the height of our triangle. The side across from the 60 degree angle is square root of 3, which is the base of our triangle, and the hypotenuse is 2. The cos identity is the ratio that utilizes the side adjacent to the reference angle over the hypotenuse, which for us is 
. That's the third choice down. Finding an "exact" value means that they want you to NOT express your answer in decimal form.
. The mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days. Suppose that the incubation ti
mes are approximately normally distributed with a standard deviation of 1 day. Complete parts (a) through(e) below.
(a) Draw a normal model that describes egg incubation times of these fertilized eggs.
(b) Find and interpret the probability that a randomly selected fertilized egg hatches in less than 23 days.
The probability that a randomly selected fertilized egg hatches in less than 23 days is _?__. (Round to four decimal places asneeded.)
(a) Draw a normal model that describes egg incubation times of these fertilized eggs.
(b) Find and interpret the probability that a randomly selected fertilized egg hatches in less than 23 days.
The probability that a randomly selected fertilized egg hatches in less than 23 days is _?__. (Round to four decimal places asneeded.)
1 answer:
Answer:
Step-by-step explanation:
Given that the mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days.
Let X be the incubation time for a type of fertilized egg kept at a certain temperature is 25 days.
X is N(25, 1)
a) Normal curve is in the attached file
b) the probability that a randomly selected fertilized egg hatches in less than 23 days
=
we convert x into Z score and use std normal distn table to find probability
i.e. we can say only 2.5% proportion will hatch in less than 23 days.
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Answer:
It would take approximately 6.50 second for the cannonball to strike the ground.
Step-by-step explanation:
Consider the provided function.
We need to find the time takes for the cannonball to strike the ground.
Substitute h(t) = 0 in above function.
Multiply both sides by 10.
For a quadratic equation of the form the solutions are:
Substitute a = -49, b = 305 and c=88
Ignore the negative value of t as time can't be a negative number.
Thus,
Hence, it would take approximately 6.50 second for the cannonball to strike the ground.
By solving a quadratic equation, it can be verified that
The owl population will disappear after 329.12 years
What is a quadratic equation?
At first it is important to know about equation
Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.
A two degree equation is known as quadratic equation.
Here, a quadratic equation needs to be solved
The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=
For population to disappear, p =0
But t = -9.115 is not possible as time cannot be negative
So, the owl population will disappear after 329.12 years
To learn more about quadratic equation, refer to the link-
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