Ask question

Ask question

All categories

3 years ago

7

you want to buy three loaves of bread that cost $1.50 each and a jar of peanit butter that $4. a jar of jelly is $2.75, but you

don't need any jelly. you have $10 how much money you have left

2 answers:

Semenov [28]3 years ago

5 0

1.50x3= 4.5

4.5+4=8.5

10-8.5= m

M=1.5

Elanso [62]3 years ago

3 0

1.50 x 3 = 4.50 (Bread)

4.00 pb

4.50+4.00= 8.50

10.00-8.50 = $1.50 left

You might be interested in

For f(x) = 4x +1 and g(x) = x2 -5, find (f 3)(x).

Georgia [21]

D!! It’s super easy I hope you can learn how to do it

4 0

3 years ago

What is the equation of the line that is parallel to the given line and passes through the point (-3, 2)?

zimovet [89]

The answer is D. 4x + 3y = -6
I first found the slope using the slope formula. Then I plugged in the values of the given coordinate and the slope I found into the point slope form equation, then I simplified. Then I manipulated the equation to get x and y on the right side, and the constant on the left side. Finally, I multiplied both sides by 3 to get rid of the fraction.

7 0

3 years ago

Read 2 more answers

frankie puts £3000 in a bank account for four years with 12% rate of interest. how much will be in the account at the end of the

Tpy6a [65]

3000x1.12
=3360
Therefore, Frankie will have £3360 percent chance for at the end if the time period

3 0

3 years ago

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

$\frac{dm}{dt} = -k\cdot m$

b) The general solution is found after separating variables and integrating each sides:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $\tau$ is the time constant and $k = \frac{1}{\tau}$

c) The time constant is:

$\tau = \frac{1690\,yr}{\ln 2}$

$\tau = 2438.155\,yr$

The particular solution of the differential equation is:

$m(t) = 10\cdot e^{-\frac{t}{2438.155} }$

d) The amount of radium after 300 years is:

$m(300) \approx 8.842\,g$

4 0

3 years ago

Read 2 more answers

Stronomers measure large distances in light-years. One light-year is the distance that light can travel in one year, or approxim

Komok [63]

This is one of those problems where you don't actually have to know anything. The only answer that is any combination of the two given numbers is the last one:
.. 8.4672*10¹³ miles

_____
That result is the product of 5.88*10¹² and 14.4.

4 0

3 years ago