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belka [17]
3 years ago
9

The cost of a computer is $849. The store is offering a 20% discount and a sales tax of 6% is added after the discount. What is

the total cost of the tv?

Mathematics
2 answers:
Hunter-Best [27]3 years ago
4 0

Answer: The total cost of the tv is $719.95

Step-by-step explanation:

Hi, to solve this problem we have to calculate the value of the discount percentage:

So:

  • $849 x 0.20 = $169.8

The next step is to subtract that result to the cost of the computer.

  • $849 -$ 169.8=$679.2

Then, we have to calculate the sale tax.

  • $679.2 x 0.06= $40.752

Finally, we add the sale tax value to the cost of the tv with the discount.

  • $679.2+ $40.752= $719.95

The total cost of the tv is $719.95

givi [52]3 years ago
3 0
$849-20%=$679
$679+6%(sales tax)=$719
$719 is the total cost of the tv
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12

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3 years ago
What is 4-(-37)+(8)-(34) Pls solve brainlliest
Anvisha [2.4K]

Answer:

15

Step-by-step explanation:

First we need to remove the parenthesis

4 + 37 + 8 - (34)

4 + 37 + 8 -34

Add 4 and 37

41 + 8 - 34

Add 41 and 8

49 - 34

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6 0
3 years ago
Is (x+7) a factor of f(x) x3-3x2+ 2x-8?
Snowcat [4.5K]

Answer:

(x+7) is not a factor

Step-by-step explanation:

we know that

If (x+7) is a factor of f(x)

then

For x=-7, f(-7)=0

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we have

f(x)=x^{3}-3x^{2} +2x-8

Substitute x=-7

f(-7)=(-7)^{3}-3(-7)^{2} +2(-7)-8

f(-7)=-343-147 -14-8

f(-7)=--512

-512\neq 0

therefore

(x+7) is not a factor

3 0
3 years ago
a room contains 156.1m of air . if the room is 8.31m long and 5.72m wide . use tabe to calculate it height​
irga5000 [103]

Answer:

height=3.28m

Step-by-step explanation:

air means volume of room

let the height of room be x.

so, volume of room= 156.1 m³

          8.31*5.72*x=156.1m³

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8 0
3 years ago
You measure 22 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 5.
lara31 [8.8K]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the true population mean textbook weight.

Number of sample, n = 22

Mean, u = 64 ounces

Standard deviation, s = 5.1 ounces

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

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= mean ± z ×standard deviation/√n

It becomes

64 ± 1.645 × 5.1/√22

= 64 ± 1.645 × 1.087

= 64 ± 1.788

The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces

The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces

Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces

3 0
3 years ago
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