Louis is walking at 4 mph. If Louis can walk 2 miles in 30 minutes, she can then walk 4 miles in an hour if you double the amount of time she is walking from 30 to 60, so you would also double the distance. She is walking at 4 miles per hour.
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
v = −
2
Step-by-step explanation: No the right answer? Let me know!
Answer:
1
answer is D
Step-by-step explanation:
we must calculate it from this equation :
x³ -9x²+27x-25 then
I have summer school work too omg!!! it’s annoying
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
