A cashier has a total of 30 bills, consisting entirely of $1 bills, $5 bills, and $20 bills. The total dollar amount of these bi
lls is $351. There are nine more $20 bills that $1 bills. How many of each bill denomination are there?
1 answer:
Answer:
Five= 9 One= 6 Twenty= 15
Step-by-step explanation:
A cashier has a total of 30 bills, made up of ones, fives, and twenties.
o+f+t=30,
The number of twenties is 9 more than the number of ones.
t=9+o,
The total value of the money is $351.
o+5f+20t=351
so we have
o+f+t=30, t=9+o,
o+5f+20t=351
f = 9, o = 6, t = 15
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