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daser333 [38]
3 years ago
9

Suppose the skaters complete one lap around the park that has the shape of a regular pentagon, what is the sum of the angles thr

ough which they turn.
Mathematics
1 answer:
KIM [24]3 years ago
4 0
That would be the same as the sum of the interior angles of the regular pentagon  which is 540 degrees.
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Write 5^4 in standard form
AfilCa [17]

Answer:

625

600+20+5

Step-by-step explanation:

<em>Parenthesis</em>

<em>Exponent</em>

<em>Multiply</em>

<em>Divide</em>

<em>Add</em>

<em>Subtract</em>

<em>From left to right.</em>

<em>Do exponent first.</em>

<em>5^4=5*5*5*5=625</em>

<em>Standard form of 5^4 is: ⇒  600+200+5</em>

<em>625 is the correct answer.</em>

<em>600+200+5 is the correct answer.</em>

4 0
3 years ago
Read 2 more answers
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
2 years ago
Read 2 more answers
Answer this question pls!! (Will give Brainliest)
AnnyKZ [126]

Answer:

D. y = 12.5x + 15

Step-by-step explanation:

Using the values provided in the table, the only equation that would be valid would be the following...

y = 12.5x + 15

That is because if we substitute any value provided in the table for x , this equation will correctly output the y value shown in the table for the attached x-value. For example, in the table 5 nights (x = 5) should have a total cost of 77.5 (y = 77.5)... Therefore, if we substitute 5 for x in the function it should give  us 77.5 which it does.

y = 12.5(5) + 15

y = 62.5 + 15

y = 77.5

3 0
3 years ago
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. A trape
aksik [14]
Use the trapezium formula 1/2( sum of parallel lines)( height )

5 0
2 years ago
Please help!!!!!!!!!!!
yawa3891 [41]

Answer:

h = 1,268 cm

Step-by-step explanation:

                   V = (π·r²·h)/3, general formula

                 83 = (π·4²·h)/3, substitute what is given V= 83 cm³ and r = 4 cm

             83 ·3 = (π· 16·h)·3/3, multiply both sides by 3 and solve 4² = 16

               249 = π·16·h, multiply 83·3 = 249 and 3/3 = 1

      249/ π·16 = h , divide both sides by π·16

1,268.146587 = h, solve

             1,268 ≈ h , is rounded to the nearest cm

6 0
2 years ago
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