Answer:
this is too old
Step-by-step explanation:
Answer:
Ok I don't know waht you mean but the answer is
Step-by-step explanation:
Answer:
x=3/2±(√11)2
x=1.5+1.65831i
x=1.5−1.65831i
Find the Solution for
2x^22−6x+10=0
using the Quadratic Formula where
a = 2, b = -6, and c = 10
x=(−b±√(b^2−4ac))/2a
x=(−(−6)±√((−6)2−4(2)(10)))2(2)
x=(6±√(36−80))/4
x=(6±√−44)/4
The discriminant b^2−4ac<0
so, there are two complex roots.
Simplify the Radical:
x=(6±2√11 i)/4
x=6/4±(2√11 i)4
Simplify fractions and/or signs:
x=3/2±(√11)2
which becomes
x=1.5+1.65831i
x=1.5−1.65831i
