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elena55 [62]
3 years ago
6

A silversmith combined pure silver that cost $33.48 per ounce with 51 oz of a silver alloy that cost $24.35 per ounce. How many

ounces of pure silver were used to make an alloy of silver costing $27.87 per ounce?
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

$38.31

Step-by-step explanation:

Given:

Pure silver that cost $33.48 per ounce used to form $24.35 alloy/ounce.

Question asked:

How many ounces of pure silver were used to make an alloy of silver costing $27.87 per ounce?

Solution:

At cost $24.35/ounce, pure silver is mixed = $33.48

At cost $1/ounce, pure silver is mixed = \frac{33.48}{24.35}

At cost $27.87/ounce, pure silver is mixed = \frac{33.48}{24.35}\times 27.87 = \frac{933.08}{24.35}  = 38.31

Thus, $38.31 ounces of pure silver were used to make an alloy of silver costing $27.87 per ounce.

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Answer:

Step-by-step explanation:

180 dollars is her pay because you divide 75 by 5 get 15 and multiply that by 12

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4 years ago
Indicate which sets are disjoint to the given set
marysya [2.9K]

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8 0
1 year ago
Seclate all the numbers that are solutions to the inequalitt w&gt;1.
natima [27]

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6 0
3 years ago
Read 2 more answers
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Karolina [17]

-43 - 4r = 3 - 27r

Add 27r to both sides. -43 - 4r + 27r = 3 -27r + 27r or -43 + 23r = 3

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Divide both sides by 23 to get r by itself. 23r / 23 = 46 / 23 or r = 2

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A local hamburger shop sold a combined total of 500 hamburgers and cheeseburgers on Wednesday. There were 50 more cheeseburgers
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500-250=250 so if there were 50 more cheeseburgers it would be 300 cheeseburgers so they would of have to sold 200 hamburgers on Wednesday to have sold 500 burgers in total do the answer is 200 hamburgers
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