Question

What is the molarity of an aqueous solution containing 40.0g of glucose in 1.5l of solution?

Answer 1

Answer:

Molarity of aqueous solution = 0.14 M

Explanation:

Molarity is defined as the number of moles of solute present in 1 L of the solution.

$M = \frac{W}{M\times \ V\ in\ L}$

Where,

W = Mass of the solute

M = Molecular mass of the solute

V = Volume of the solution

Volume of the solution = 1.5 L

Mass of glucose = 40.0 g

Molecular mass of glucose = 180.16 g/mol

$M = \frac{40.0}{180.16\times 1.5}$

           = 0.1480 M

            = 0.14 M

Answer 2

The  molarity  of  aqueous   solution  containing  40.0g  of  glucose  in  1.5 L  of   solution  calculated  as  follows

molarity  = moles/volume  in  liters

find  the  moles  of  glucose  = mass  /molar  mass
=  40/  180.06  =  0.222 moles
 molarity  is  therefore = 0.222/1.5 =  0.148 M