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cestrela7 [59]
3 years ago
5

A chemist prepares a solution of silver nitrate by measuring out of silver nitrate into a volumetric flask and filling the flask

to the mark with water. calculate the concentration in of the chemist's silver nitrate solution. round your answer to significant digits.
Chemistry
1 answer:
Snezhnost [94]3 years ago
8 0

Amount of silver nitrate taken = 269.μmol AgNO_{3}

Volume of the solution = 300. mL

Concentration of a solution is generally expressed in terms of molarity. Molarity is defined as the moles of a substance present per liter of the solution.

Molarity = \frac{Moles of solute}{Volume of solution(L)}

We want the concentration in millimoles/L.

Converting μmol to millimol solute:

269.μmol * \frac{1 millimol}{1000 micromol} = 0.269 millimol

Volume from mL to L: 300. mL * \frac{1 L}{1000 mL} = 0.300 L

Therefore concentration of the chemist's solution = \frac{0.269 millimol}{0.300 L} =  0.897 \frac{millimol}{L}

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Explanation:

Using the dilution equation:

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<em>2 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

<em />

In order to prepare 10 mL, 10 μM from 25 μM stock,

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Initial volume = 100/25 = 4 mL

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<em>8 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

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