Question

A chemist prepares a solution of silver nitrate by measuring out of silver nitrate into a volumetric flask and filling the flask to the mark with water. calculate the concentration in of the chemist's silver nitrate solution. round your answer to significant digits.

Answer 1

Amount of silver nitrate taken = 269.μmol $AgNO_{3}$

Volume of the solution = 300. mL

Concentration of a solution is generally expressed in terms of molarity. Molarity is defined as the moles of a substance present per liter of the solution.

$Molarity = \frac{Moles of solute}{Volume of solution(L)}$

We want the concentration in millimoles/L.

Converting μmol to millimol solute:

$269.$μ$mol * \frac{1 millimol}{1000 micromol}$ = 0.269 millimol

Volume from mL to L: $300. mL * \frac{1 L}{1000 mL} = 0.300 L$

Therefore concentration of the chemist's solution = $\frac{0.269 millimol}{0.300 L} = 0.897 \frac{millimol}{L}$