Your gonna half to space this out in order for me to answer if you don’t mind. I’ll answer in the comments
B. An equal amount of protons and electrons
corrected question:
A chemist determined by measurements that 0.03 moles of calcium sulfide participate in a chemical reaction. Calculate the mass of calcium sulfide that participates
Answer:
Explanation:
number of moles of CaS
molar mass of CaS = 40+32 = 72g/mol
number of moles = mass/ molar mass
mass = number of moles * molar mass
mass = 0.03 *72
mass of calcium sulfide = 2.16g
Answer:
ty po hehe
Explanation:
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