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Arturiano [62]
3 years ago
13

Identify the reaction type and the products. Al+F2 ->

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

redox and AlF2

Explanation:

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Suppose that a certain biologically important reaction is quite slow at physiological temperature (37 oC) in the absence of a ca
Oksi-84 [34.3K]

Answer:

30 kJ

Explanation:

Arrhenius equation is given by:

k=Aexp(-Ea/RT)\\

Here, k is rate constant, A is Pre-exponential factor, Ea is activation energy and T is temperature.

taking natural log of both side

ln k = ln A - Ea/RT

In Arrhenius equation, A, R and T are constant.

Therefore,

ln\frac{k_2}{k_1} =\frac{Ea_1-Ea_2}{RT}

Ea_1-Ea_2 is the  lowering in activation energy by enzyme,

R = 8.314 J/mol.K

T = 37°C + 273.15 = 310 K

\frac{k_2}{k_1} =1\times 10^5

ln 1\times 10^5 =\frac{Ea_1-Ea_2}{RT}\\{Ea_1-Ea_2} = 11.512 \times 8.314 \times 310\\=29670\ J\\=30\ kJ

4 0
4 years ago
A gas exerts a pressure of 1.35 atm. What is the equivalent measures in mmHg?
Pie
1.35atm(760mmHg/1atm)=1026mmHg
8 0
3 years ago
Which wave has the greatest distance from trough to trough?
mylen [45]

Answer:

a

Explanation:

8 0
3 years ago
Help needed Assignment is due Justify that H2SO4 is Arrhenius acid and KOH is Arrhenius base.
irakobra [83]

Answer:

<u><em>Arrhenius Acid:</em></u>

According to Arrhenius concept, Acids are proton donors.

Since H₂SO₄ have a proton (H⁺ ion) and it can donate it to be made a sulphate ion, So it is an Arrhenius acid.

See the following reaction =>

<u><em>H₂SO₄ + H₂O => HSO₄ + H₃O⁺</em></u>

<u><em>Arrhenius Base:</em></u>

An Arrhenius base is a a proton acceptor.

KOH accepts the proton to to made to KOH₂ and a proton acceptor.

See the following reaction =>

<u><em>KOH + H₂o => KOH₂ + OH⁻</em></u>

<u><em></em></u>

6 0
3 years ago
All of the following are true statements about catalysts except: Select one: a. A catalyst will speed the rate-determining step
liberstina [14]
<span>d. A catalyst will be used up in the reaction is wrong,
amount of catalyst should not change</span>
6 0
4 years ago
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