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Sladkaya [172]
3 years ago
7

What does 1/4 subtract 1/11 equal

Mathematics
1 answer:
Anastasy [175]3 years ago
4 0

Answer:

7/44

Step-by-step explanation:

you can't simply subtract 1/11 from 1/4 because the denominators are not the same . Meaning you have to convert the denominators into a similar number. Transformers in even number and a consecutive number while 11 is an odd number and a prime number they don't really agree on anything 11 can only be divided by itself and 1 wall for can be divided by a multitude of things. Because of them not exactly agreeing on any specific category , you have to multiply them by each other . So your new fractions should look like 11 / 44 and 4 / 44 . from there you can easily subtract 4 from 11 and get 7 / 44 now normally you can reduce these types of fractions but because seven can only be divided by itself and 44 is not a factor of 7 you cannot reduce this fraction .

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<h2>        43.4° and 46.6°</h2>

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For what value of constant c is the function k(x) continuous at x = 0 if k =
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The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

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Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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