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Yuki888 [10]
3 years ago
7

Enzyme A and Enzyme B both catalyze the same reaction. If Enzyme A has a larger turnover number than Enzyme B, then which enzyme

, if either, has a higher catalytic efficiency?
Enzyme B is more efficient because it's turnover number is smaller.
Enzyme A is more efficient because it's turnover number is larger.
Not enough information is provided to know for certain.
Chemistry
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

Enzyme A, if we assume the concentration of the enzymes (A and B) are the same

Explanation:

As Enzyme turnover number is defined as the number of chemical conversions of substrate per second that a single enzyme can perform in its catalytic site, for a given enzyme concentration, we can say that the Enzyme A has a higher catalytic efficiency. This is true only if [Enzyme A] = [Enzyme B]

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A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
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7. What happen if we don't have water?
Ahat [919]

Answer:

our bodies will dehydrate causing us to die a dreadfully excruciating painful death

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Answer:

c) the study of matter and the changes it undergoes

Explanation:

Chemistry -

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Black_prince [1.1K]

Answer:

4,572.67

Explanation:

11 divided by 1000= 90.90

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44-51.300=6.300

6.300 x 90.90=572.67

4000 + 572.67 = the answer

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Nonamiya [84]

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