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3 years ago

How is 0.00036 written in scientific notation?

1 answer:

4 0

3.6 x 10^-4
I am writing this sentence because the answer does not reach the 20 character limit. Thank you have nice day! :D Cx :P

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How do you solve this? I am so confused. This is Chemistry 1 HON and its dimensional analysis. It would help me so much if someo

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4 years ago

Heterotrophic bacteria obtain food by

BARSIC [14]

Heterotrophic cells must ingest biomass to obtain their energy and nutrition. Heterotrophic microorganisms mostly feed upon dead plants and animals, and are known as decomposers. ... Some animals also specialize on feeding on dead organic matter, and are known as scavengers or detritivores. Hope this was helpful.

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4 years ago

4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60

Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

t = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Half-life of Co-60 = 5.3 years

Input the value :

$\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}$

8 0

3 years ago

For each compound determine whether it is organic or inorganic. C10h16kno9s2 naaso2 hsicl3 (ch)4as2 (bio)2co3 h2p2o7 h2o co2 c6h

Sindrei [870]

a. Organic: C₁₀H₁₆KNO₉S₂; (CH₃)₄As₂; C₆H₁₂O₆

b. Inorganic: NaAsO₂; HSiCl₃; (BiO)₂CO₃; H₂P₂O₇; H₂O; CO₂

Compounds containing <em>both C and H</em> are organic.

Compounds that are <em>not organic</em> are inorganic.

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3 years ago

Based on the molecular formula, determine whether each compound is an alkane, alkene, or alkyne. (Assume that the hydrocarbons a

topjm [15]

Answer:

a. alkyne

b. alkane

c. alkyne

d. alkene

Explanation:

The general formula for each class of compound is given below

Alkane: $C_nH_{2n+2}$

Alkene: $C_nH_{2n}$

Alkyne: $C_nH_{2n-2}$ (assuming single multiple bonds)

Now let us classify according to the above formulas:

a. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne

b. It has two hydrogen atoms more than the two times of carbon atoms hence, it's alkane

c. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne

d. It has hydrogen atoms two times of carbon atoms hence, it's alkene

5 0

3 years ago

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