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3 years ago

How is 0.00036 written in scientific notation?

1 answer:

4 0

3.6 x 10^-4
I am writing this sentence because the answer does not reach the 20 character limit. Thank you have nice day! :D Cx :P

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Is helium a metal, non metal or metalloid?

ioda

Helium is a nonmetal. There are several reasons for this, it is unable to donate electrons and It has an extremely low melting point.

4 0

3 years ago

Imagine an alternate universe where the value of the Planck constant is 6.6207 x 10^-36 J*s.

Salsk061 [2.6K]

Answer:

See explanation

Explanation:

According to Louis de Broglie, matter has an associated wavelength. He was the first scientist to establish the idea of wave-particle duality or wave- particle paradox.

The display of wavelike properties by objects in the universe is dependent on the magnitude of the of the mass of the body. Small objects have a large associated wavelength and can be described completely by quantum mechanics.

A buckyball with a mass of 1.2 x 10-21 g, 0.7 nm wide, moving at 38. m/s has a very small mass and significant associated wavelength hence the system can be completely described by quantum mechanics.

5 0

3 years ago

Explain the first three steps of scientific inquiry

erastovalidia [21]

1. Observation-- making observations and taking notes about what you see, smell, hear, think, etc.
2. Question-- developing a question to test your observations.
3. Hypothesis-- creating an educated guess as to the answer of your question.

5 0

3 years ago

What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97.6˚C) and 1 atm

Rudiy27

Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K

Explanation :

Formula used :

$\Delta S=\frac{\Delta H_{freezing}}{T_f}$

where,

$\Delta S$ = change in entropy

$\Delta H_{fus}$ = change in enthalpy of fusion = 3.17 kJ/mol

As we know that:

$\Delta H_{fus}=-\Delta H_{freezing}=-3.17kJ/mol=-3170J/mol$

$T_f$ = freezing point temperature = $-97.6^oC=273+(-97.6)=175.4K$

Now put all the given values in the above formula, we get:

$\Delta S=\frac{\Delta H_{freezing}}{T_m}$

$\Delta S=\frac{-3170J/mol}{175.4K}$

$\Delta S=-18.07J/mol.K$

Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K

4 0

3 years ago

If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(you will n

Harman [31]

Sodium(Na) is the limiting reagent.

<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

$2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}$

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

to learn more about Limiting Reagent go to - brainly.com/question/14222359

#SPJ4

4 0

1 year ago