. A compound name includes the term ""ethylheptane"". How many total carbons are present in the use of this term? (a) 2 (b) 7 (c
1 answer:
Answer : The total number of carbons present in ethylheptane are, 9.
Explanation :
The basic rules for naming of organic compounds are :
First select the longest possible carbon chain.
For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
A suffix '-ane' is added at the end of the name of alkane.
If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain.
The given compound is, ethylheptane.
In the given compound, the prefix used is 'hept' that means longest possible carbon chain number will be 7 and suffix '-ane' shows that the compound belongs to alkane group and the substituent 'ethyl' is also attached to the main carbon chain. Thus, the total number of carbons present in ethylheptane are, 9.
Hence, the total number of carbons present in ethylheptane are, 9.
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Explanation:
Boiling point is defined as the temperature when the vapor pressure of liquid becomes equal to the atmospheric pressure surrounding the liquid. And, during this temperature liquid state of substance changes into vapor state.
More stronger is the presence of intermolecular forces within the molecules of a compound more heat is required by it to break the bond. Hence, boiling point will also increase.
(a) As both Ne and Xe are noble gases and has intermolecular dispersion forces. But as the atomic size of Xe is more than the atomic size of Ne and we know that dispersion forces increases with increase in size.
Hence, boiling point of Xe will be more than the boiling point of Ne.
(b) Both and
are non-polar in nature with intermolecular dispersion forces. So, more is the molecular weight of a compound more heat will be required by it in order to break the bonds.
As molecular weight of is more than the molecular weight of
. Hence,
will have high boiling point.
(c) Molecular weight of is 16 g/mol and molecular weight of
is 35 g/mol.
Hence, will have high boiling point due to the presence of high molecular weight as compared to
and more strong dispersion forces.
(d) is a covalent compound so, it will also be non-polar in nature. Hence, it has weak intermolecular dispersion forces. On the other hand, LiF is an ionic compound and it has strong intermolecular forces of attraction due to the presence of opposite charges on the combining atoms.
Hence, LiF will have high boiling point as compared to .
(e) Both and
are polar molecules in which dipole-dipole forces does exist. Since, nitrogen atom is more electronegative than phosphorous atom so, it will have stronger hydrogen bonding and strong intermolecular forces.
Hence, will have high boiling point as compared to
.