For

to be continuous at

, you need to have the limit from either side as

to be the same.


If

and

, then the limit from the right would be

, so the answer to part (1) is no, the function would not be continuous under those conditions.
This basically answers part (2). For the function to be continuous, you need to satisfy the relation

.
Part (c) is done similarly to part (1). This time, you need to limits from either side as

to match. You have


So,

and

have to satisfy the relation

, or

.
Part (4) is done by solving the system of equations above for

and

. I'll leave that to you, as well as part (5) since that's just drawing your findings.
draw an imaginary line down from the 1 dimension so you have a rectangle that is 1 by 24
area = L x w = 24 * 1 = 24 square units
now you have a triangle that is 7 at the bottom and 24 tall
area of triangle = 1/2 x base x height
so you have 1/2 * 7 * 24 which =84 square units
total area = 84 + 24 = 108 units^2
please mark brainliest
Answer:
50.27
Step-by-step explanation:
area of a circle: pi X r^2
r= radius
7x-4=5x+15
-5x on both sides
2x-4=15
add four to both sides
2x=19
divide both sides by 2 to isolate x
x=9.5
2-3 is -1. difference between two rational numbers that make a negative