Answer: 0.0516
Step-by-step explanation:
Given : The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of
.
The probability mass function for Poisson distribution:-
For x= 15 and
, we have

Hence, the probability that exactly 15 defective components are produced in a particular day = 0.0516
3x + 2y = 12
subtract 3x from both sides
2y = -3x + 12
divide all terms by 2 so that you can have only the y on the left side
y = -3/2x + 6
And that is your answer!
Hope this helped!! :)
Step-by-step explanation:
I hope this helps. good luck
Answer:
6.5
Step-by-step explanation:
3X5=15
97.5/ 15 = 6.5