Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Let x represent the height of the model.
We have been given that a construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. We are asked to find the height of the model, if the building is expected to be 200 feet tall.
We will use proportions to solve our given problem as:
Upon substituting our given values, we will get:
Therefore, the model will be 18.75 inches tall.
Answer:
67.2
Step-by-step explanation:
You take 100 and minus 32.8
it is the same as 10minus 8 is 2 so we right the 2. then 9-2 is 7. and 9-3 is 6
99.(1)0
-
32.8
---------------
67.2
Answer:
The correct answer is 2.912 cm.
Step-by-step explanation:
A company is designing a new cylindrical water bottle.
Volume of a cylinder is given by π × × h, where h is the height of the cylinder and r is the radius of the cylinder.
The volume of each bottle will be 211 .
The height (h) of the water bottle be 7.9 cm.
Let the radius of the bottle be r cm.
∴ π × × h = 211 ; (π = 3.15)
⇒ × 24.885 = 211
⇒ r = 2.912
The radius of the water bottle is 2.912 cm.