The ladder, leaning against the building, forms a right triangle with height "a" being the distance from the ground to the window, and hypotenuse "c" being the length of the ladder.
Because it's a right triangle, we can use trigonometric ratios to find the angles we're missing.
For part A), to solve for the angle between the base of the ladder and the ground, you'll want to use sine, because we know the lengths of the opposite side and the hypotenuse.
Sin(x) = a/c , solve for angle x in degrees or radians.
For part B), finding the angle between the top of the ladder and the building, remember that the sum of the angles in a triangle is 180 degrees, or pi radians, depending on which unit your teacher prefers.
Assuming degrees, we can say that angle y = 180-90-x. You are simply subtracting the two known angles to find the third.
For part C) use the Pythagorean theorem. You're looking for the length of the base, "b". Recall:
a^2 + b^2 = c^2
Plug in the known values, and solve for b.
I don’t understand the links? Like is that trolling????
Answer:
m<1 =95
m<2 = 130
Step-by-step explanation:
I take it you want the size of <1 and <2?
<ABC + 95 = 180 Same straight line.
<ABC = 180 - 95 Subtract 95 from both sides.
<ABC = 85 Combine
===========================
<1 + <ABC = 180 Interior angles on the same side of the transversal = 180
<1 + 85 = 180
<1 = 180 - 85
<1 = 95
=============================
Givens
<ABC = 85
m< 1 = 95
<ADC = 50 Given
m<2 = ?
m<2 + <ABC + m<1 + 50 = 360 The four angles of a quadrilateral add to 360
m<2 + 85 + 95 + 50 = 360
m<2 + 230 = 360
m<2 = 360 - 230
m<2 = 130
School is not a a proper noun so it will start with a lowercase letter
Answer:
Step-by-step explanation:
We want to simplify:
The trick is that when a negative index in the numerator comes to the denominator , it becomes positive.
The vice-versa is also true.
That is:
and
We simplify to get:
The last choice is correct.
