All categories

4 years ago

How do you calculate the daily periodic rate?

2 answers:

8 0

<span>A daily periodic interest rate is calculated by dividing the annual percentage rate, or APR, by either 360 or 365, depending on the card issuer.</span>

skad [1K]4 years ago

7 0

Answer:

First we need to know what's APR.

APR refers to a annual periodic rate that's charged in a credit card. It changes depending on the company. So, the daily periodic rate can be calculated by dividing the APR of the credit car by 360 or 365, depending on the credit card companies.

So, basically, you need to call the company and ask about the APR and ask if the use 360 or 365 days to calculate the daily periodic rate, then do the division.

You might be interested in

What is the answer to this?

katrin [286]

Answer:

$\huge\boxed{-28}$

Step-by-step explanation:

We can substitute the given values of $a$ , $b$ , and $c$ to find the value of this expression.

$-4 | a + b - c|$

$-4 | 3 + (-2) - (-6)|$

We know that <em>two negatives make a positive. </em>This means that $-2 - (-6)$ will be the same this as $-2+6$

$-4 | 3 + -2 + 6|$

Adding a negative is the same as subtracting a positive.

$\4 | 3-2+6|\\\\3-2+6 = 7$

$-4 \cdot 7 = -28$

Hope this helped!

7 0

3 years ago

Read 2 more answers

Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min

kow [346]

Answer:

$h=40t+9700$

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, $t_1=15$ min, the elevation, $h_1= 10,300$ feet and

at the time $t_2= 30$ min, the elevation, $h_2=10,900$ feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let $h$ be the elevation at any time instant $t$ , so the linear relation among these quantities is

$h=mt+C_0\;\cdots(i)$

where $m$ is the rate of change of elevation with respect to time and $C_0$ is constant.

The change in the elevation, $\Delta h=h_2-h_1= 10,900-10,300=600$ feet.

and the change in time, $\Delta t=t_2-1_1=30-15=15$ min.

So, change in the elevation in unit time,

$m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40$ feet/min.

Now, from equation (i)

$h=40t+C_0$

As the elevation, $h=h_1$ at time $t=t_1$ , so

$10,300=40\times15+C_0$

$\Rightarrow C_0=9700$

Hence, the required equation is

$h=40t+9700$

where the elevation, $h$ , is in feet and time, $t$ , is in minutes.

3 0

3 years ago

If you want to convert quarts to cups, should you multiply or divide?

bonufazy [111]

<h3>Answer: Multiply by 4</h3>

This is because 1 quart = 4 cups

So if you had say 3 quarts, then it converts to 3*4 = 12 cups.

4 0

2 years ago

Read 2 more answers

A scale model of a human heart is 190 Inches long. The scale is 34 to 1. How many Inches long is the actual

Alika [10]

Answer:

6 inches long

Step-by-step explanation:

190/x = 34/1

34x = 190

x= 5.588235294

rounded to the nearest whole number is 6

6 0

3 years ago

Town C is 2 miles east of town A and 2 miles south of Town B as in the figure at right. which of the following is the best estim

Ray Of Light [21]

Since C is 2mi east of A and 2mi south of B, the shortest distance from A to B would be a straight line which is equal to the hypotenuse of a right triangle with a base of 2mi and a height of 2mi..

d^2=x^2+y^2

d^2=2^2+2^2

d^2=4+4

d^2=2*4

d=√(2*4)

d=2√2 mi (exact)

d≈2.83 mi (to nearest hundredth of a mile)

5 0

3 years ago