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babunello [35]
3 years ago
5

What is the mode for the data set?

Mathematics
1 answer:
koban [17]3 years ago
3 0
E. None, since none of the numbers are repeating (which is how you find the mode)
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IM GIVING 30 POINTS PLZ HELP ASAP<br> GIVING BRAIN TOO!
yawa3891 [41]

Answer:

<em>x</em> = 28 Hours

Step-by-step explanation:

if you start with 20 bags done then you take that away from the 1000 and you have 980. Then you do  35x <em>x </em>or 35x28 = 980.

3 0
3 years ago
3 4/7 minus 2 1/5 by rounding to the nearest half
mylen [45]

Answer:

1 \frac{13}{35}

Step-by-step explanation:

3 \frac{4}{7} -  2 \frac{1}{5}

you can solve for the fractions first, but you have to give them a common denominator

\frac{20}{35}- \frac{7}{35}

= \frac{13}{35} which is in simplest form

then solve for the whole numbers

3-2=1

therefore, the answer is 1 \frac{13}{35}

6 0
3 years ago
(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).
Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = \frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use <u>product rule</u>,i.e., \frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}

this will give <em>k'(x)=f'(x)g(x) + f(x)g'(x)</em>

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)} ]. Since m(x) has a function g(x) in the denominator so we need to use <u>division rule</u> to differentiate m(x). Division rule is as follows : \frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}

this will give <em>m'(x) = \frac{1}{2}\times\frac{f'(x)g(x) - f(x)g'(x)}{g^{2}(x) }</em>

on substituting the value x=5, we will get the value of m'(5).

{for expressing the value in terms of numbers first we need to know the value of f(5), g(5), f'(5) and g'(5) in terms of numbers}

{NOTE : in m(x), g(x) ≠ 0 for all x in domain to make m(x) defined and even m'(x) }

{ NOTE : \frac{\mathrm{d} f(x)}{\mathrm{d} x}=f'(x) }

4 0
3 years ago
Stevens bank account balance was $212 at the beginning of the month he withdrew $63,$74 and $39 he also deposited $105 and $86 w
Natali5045456 [20]

Answer:

$227

Step-by-step explanation:

First we can add up the withdrawals(63, 74, and 39) which is 176. We can then subtract 176 from 212 to get 36.

So, after the withdrawals Steven has 36 dollars.

We can add the deposits together to get 191. We can then add 191 to 36 to get 227.

8 0
3 years ago
Probability please help! (Picture)
Vladimir79 [104]
I think its 50 percent. Hope this helps.
3 0
3 years ago
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