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3 years ago

15

REWRITE EACH EQUATION TO ISOLATE THE INDICATED VARIABLE

1 answer:

lisabon 2012 [21]3 years ago

5 0

The answer to the question

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Who can tutor me for free

krok68 [10]

Answer:

Do not ask for free tutoring (Nobody will really do it)

Step-by-step explanation:

Just use Brainly! Ask for questions and explanations and do what you can to get your work done. After that if you need further help then ask a parent/guardian/sibling or someone you know for help and if that doesn't work then come back to this. Hope this helps.

4 0

2 years ago

a construction crew built 4 1/2 miles of Road and 3 3/8 days. What is the unit rate in miles per day? Write your answer as a fra

sineoko [7]

The construction crew took $3\frac{3}{8}$ days to build $4\frac{1}{2}$ miles of road.

Therefore, in 1 day, the crew built $\frac{4\frac{1}{2} }{3\frac{3}{8} }$ miles of road

= $\frac{\frac{9}{2} }{\frac{27}{8} } =\frac{9}{2}times\frac{8}{27}=\frac{4}{3}$ miles of road

Thus, the required rate is $\frac{4}{3}$ miles or $1\frac{1}{3}$ miles per day.

5 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

What is the measure of XYZ (MULTIPLE CHOICE)

Aliun [14]

The measure of XYZ is:

C. 120

7 0

3 years ago

Find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times

irakobra [83]

Two Consecutive Odd Numbers: D, D+2

(D+2) + 2D = 4D - 27
D + 2 + 2D = 4D - 27
3D + 2 = 4D - 27
3D + 29 = 4D
29 = D

Two Consecutive Odd Numbers are 29, 31

Check. . 31 + 2(29) = 4(29) - 27
..................31 + 58 = 116 - 27
.................89 = 89 ..... CORRECT!

4 0

3 years ago