Answer:
There is a 54.328% probability that the next person will purchase no more than one costume.
Step-by-step explanation:
Since in a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance, and Olivia sets up a website where players can buy and sell these costumes online, and information about the number of people who visited. the website and the number of costumes purchased in a single day states that 144 visitors purchased no costume, 182 visitors purchased exactly one costume, and 9 visitors purchased more than one costume, to determine, based on these results, the probability that the next person will purchase no more than one costume as a decimal to the nearest hundredth, the following calculation must be performed:
144 + 182 + 9 = 335
335 = 100
182 = X
182 x 100/335 = X
18,200 / 335 = X
54,328 = X
Therefore, there is a 54.328% probability that the next person will purchase no more than one costume.
Answers:
Ava’s graph is a vertical translation of f(x) = x^2.
Ava’s graph moved 4 units from f(x) = x^2 in a positive direction.
Ava’s graph has a y-intercept of 4.
Given:
Ava graphs the function
.
Victor graphs the function 
To find y intercept we plug in 0 for x

= 4
So ,Ava’s graph has a y-intercept of 4.
Ava graphs the function 
If any number is added at the end then the graph will be shifted up. 4 is added at the end so there will be vertical translation.
Hence , Ava’s graph is a vertical translation of f(x) = x^2. Also Ava moved 4 units up from f(x) = x^2 in a positive y- direction.
Victor graphs the function 
If any number added with x then the graph will be shifted left. the graph will be shifted in negative x direction.
Answer:
I KNOWW THE ANSWER!!
Step-by-step explanation:
Answer:
x=2
Step-by-step explanation:
3+2x=13-3x
+3x +3x
3+5x=13
-3 -3
5x=10
/5 /5
x=2
Hope this helps! :D
1 and half hour
= 60 minutes+ 30 minutes
= 90 minutes
Now,
Uzanne need 15 minutes to do 10 problems
Uzanne need 1 minute to complete 10/15 problems
Uzanne need 90 minutes to do
= (10/15)*90
=(2/3)*90
=2*30
=60 problems