1 and 50
2 and 25
2 and 50
5 and 50
10 and 50
25 and 50
300=2×2×5×5×3
We observe that 2 and 5 are grouped in pairs and the 3 is left unpaired.
If we multiply 300 by the factor 3 then
300×3=2×2×5×5×3×3
900=2×2×5×5×3×3 which is a perfect square.
∴ Required number is 3
root of 900 =30
Answer:
f(6) ≈ 31
Step-by-step explanation:
If f(x) varies directly with x, we can write f(x) this way:
f(x) = kx
Using the given values, we can find k:
f(25) = k×25 = 130
k = 130/25 = 5.2
Then for x = 6, we have ...
f(x) = 5.2x
f(6) = 5.2×6 = 31.2
Rounded to the nearest whole number, ...
f(6) ≈ 31
Answer:
There are no real solutions to this equation because the square root of a negative number is not real. So answer B
Step-by-step explanation:
Step-by-step explanation:
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