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frez [133]
3 years ago
5

2)simplify: y^6 / y^2 a: y^8 b: y^4 c: y^3 ( my answer) d: y^1

Mathematics
1 answer:
pogonyaev3 years ago
3 0
Y^6 / y^2 = y^(6 - 2) = y^4
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Help me<br> ..........,..........................
saw5 [17]
Hi there!
The answer you're looking for is
218 because 10+4 exponent 4 - 6 x 8 that's the parenthesis then you find the answer to the exponent = 10 + 256 - 48 Then you add and subtract 10+256-48=218 Hope it helps <3
3 0
3 years ago
Explain how probability can be used to help a sales person forecast future sales.
Naily [24]

Answer with explanation:

A salesperson can use probability to get an idea of his business as using probability he can estimate his sale of the next month as well, based on the present and previous months sales.

It can help him sort issues or errors he is facing in his business as he will get a complete idea of his business using probability.

Moreover, he can forecast future sales by using a technique which involves assigning percentages or weighting benchmarks in sales cycle, so that he can estimate the expected revenue generated.

For example:

A supermarket sales person can assign probabilities to benchmarks in sale cycle as providing needs analysis (25 % probability), adding new product (50%Probability) , Remove a product ( 75 % probability), closing sale (100% Probability) . If these probabilities are large, then forecast model can be objective.

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So just like that by assigning probabilities to benchmarks, a sales person can forecast future sales

6 0
3 years ago
Read 2 more answers
How do you check the answer for the division problem eight divided by three hundred?
lawyer [7]

Answer:

you multiply the quotient times the divisor and your awnser should be the same as the dividend

Step-by-step explanation:

7 0
3 years ago
Quadratic Equations<br> How do I solve a quadratic equation?
malfutka [58]
There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
 ex:        x^2+ 4x + 3 =0
             (x+3) (x+1) = 0
              x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)

2) The other way to solve a quadratic function is by using a formula:
    given: ax^2 +bx +c=0
    x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
    
 ex: 3x^2 + 4x -2=0
    x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
                                                        and
                                              x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
5 0
3 years ago
What is the missing exponent in the equation 2? = 16?
IRISSAK [1]

Answer:

4

Step-by-step explanation:

2x2x2x2 = 16

5 0
4 years ago
Read 2 more answers
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