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egoroff_w [7]
3 years ago
15

Each of 7 students reported the number of movies they saw in the past year. Here is what they reported.

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0

Answer:

mean=12

Step-by-step explanation:

First, order the data like so.

5, 7, 12, 12, 16, 17, 17

Then add them all up.  

It is a sum of 86.

Finally divide

86/7=12.2

Since 12.2 movies aren't possible, let's say the mean is 12

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You have to find the LCM (least common multiple) of both numbers.

3: 3, 6, 9, 12, 15
5: 5, 10, 15

ivan and gavin will be together at the gym on the 15th day.
8 0
3 years ago
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You bought a magazine for $5 and some candy bars for $4 each. You spent a total of $29. How many candy bars did you buy?
Yakvenalex [24]
6 candy bars because 6 times 4 is 24 plus the 5 for the magazine.
6 0
3 years ago
N - 1/8 = 3/8<br> I am no smort and i forgot to study for a test =|
sdas [7]

Answer:

  • \boxed{\sf{n=\dfrac{1}{2}=0.5 }}

Step-by-step explanation:

Isolate the term of n from one side of the equation.

<h3>n-1/8=3/8</h3>

<u>First, add by 1/8 from both sides.</u>

n-1/8+1/8=3/8+1/8

<u>Solve.</u>

<u>Add the numbers from left to right.</u>

3/8+1/8=4/8

<u>Common factor of 4.</u>

4/4=1

8/4=2

<u>Rewrite as a fraction.</u>

=1/2

n=1/2

<u>Divide is another option.</u>

1/2=0.5

n=1/2=0.5

  • <u>Therefore, the final answer is n=1/2=0.5.</u>

I hope this helps you! Let me know if my answer is wrong or not.

3 0
2 years ago
Quadrilateral LMNO is a rectangle. Find MN.
Cloud [144]
(4x-1)=(5x-8)
x=7

4(7)-1= 27

5(7)-8= 27

So the answer is 27

<span>MN = 27</span>

3 0
3 years ago
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There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

7 0
4 years ago
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