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2 years ago

12

A number is at random from 1 to 10 find the probability of selecting a multiple of 2

1 answer:

hichkok12 [17]2 years ago

6 0

Answer:

1/2

Step-by-step explanation:

The multiples of 2 in between 1 and 10: 2, 4, 6, 8, 10

5 out of 10 are multiples of 2

5/10 = 1/2

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Advocard [28]

Answer:

y = 38 + 72t - 16t^2

Step-by-step explanation:

So, solve for t when y=48.

The max height is of course, when t = 64/32 = 2.

5 0

2 years ago

Noah and his friend Tyree are involved in a math challenge. Noah solves 115 problems in 2 min. Tyree solves 172.5 problems in 3

Natasha2012 [34]

C) They solve the same number of problems per minute

172.5 Divided by 2

115 divided by 2

= 57.5

6 0

2 years ago

Read 2 more answers

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

A ship traveled 120 km with the current, and then turned around and traveled back, spending 5h and 24 min on its trip. Find the

nadya68 [22]

Yah same im also an RSM student. 8th Honors?

7 0

3 years ago

Shawna works at a local pet store. When she works 3 hours, she earns $27. When she works 8 hours, she earns $72. Which equation

finlep [7]

Answer:

4

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers